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ラベル 偏微分 の投稿を表示しています。 すべての投稿を表示
ラベル 偏微分 の投稿を表示しています。 すべての投稿を表示

極座標ラプラシアンの導出

original: https://www.youtube.com/watch?v=NEI-U0aF3nY

極座標ラプラシアンの導出

直交座標\((x,y,z)\)と極座標\((r,\theta,\psi)\)の関係式

$$\begin{eqnarray} \left\{ \begin{array}{l} x&=&r \sin{\theta}\cos{\psi}\;\cdots\;a \\y&=&r \sin{\theta}\sin{\psi}\;\cdots\;b \\z&=&r \cos{\theta}\;\cdots\;c \end{array} \right. \end{eqnarray}$$ $$\begin{eqnarray} \left\{ \begin{array}{l} r^2&=&x^2+y^2+z^2\;\cdots\;d \\\cos{\theta}&=&\frac{z}{r}\;\cdots\;e \\\tan{\psi}&=&\frac{y}{x}\;\cdots\;f \end{array} \right. \end{eqnarray}$$

\(\frac{\partial r}{\partial x}\)を求める

\(d\)の両辺を\(x\)の偏微分をとる. $$\begin{eqnarray} \frac{\partial }{\partial x}r^2&=&\frac{\partial }{\partial x}\left(x^2+y^2+z^2\right) \\2r\frac{\partial r}{\partial x}&=&2x \\\frac{\partial r}{\partial x} &=&\frac{\cancel{2}x}{\cancel{2}r}=\frac{x}{r}=\sin{\theta}\cos{\psi}\;\cdots\;aより \end{eqnarray}$$

\(\frac{\partial \theta}{\partial x}\)を求める

\(e\)の両辺を\(x\)の偏微分をとる. $$\begin{eqnarray} \frac{\partial }{\partial x}\cos{\theta}&=&\frac{\partial }{\partial x}\frac{z}{r} \\-\sin{\theta}\frac{\partial \theta}{\partial x}&=& z\frac{\partial }{\partial x}\frac{1}{r} \\&=&z\frac{\partial }{\partial r}\left(\frac{1}{r}\right)\frac{\partial r}{\partial x} \\&=&-\frac{z}{r^2}\frac{\partial r}{\partial x} \\&=&-\frac{z}{r^2}\;\sin{\theta}\cos{\psi}\;\cdots\;一つ前の\frac{\partial r}{\partial x}の結果 \\\frac{\partial \theta}{\partial x}&=&\frac{z\cos{\psi}}{r^2}=\frac{z}{r}\frac{\cos{\psi}}{r} \\&=&\frac{\cos{\theta}\cos{\psi}}{r}\;\cdots\;eより \end{eqnarray}$$

\(\frac{\partial \psi}{\partial x}\)を求める

\(f\)の両辺を\(x\)の偏微分をとる. $$\begin{eqnarray} \frac{\partial }{\partial x}\tan{\psi}&=&\frac{\partial }{\partial x}\frac{y}{x} \\\frac{1}{\cos^2{\psi}}\frac{\partial \psi}{\partial x} &=&y\frac{\partial }{\partial x}\frac{1}{x} \\&=&y\left(-\frac{1}{x^2}\right) \\&=&-\frac{y}{x}\frac{1}{x} \\&=&-\tan{\psi}\left(\frac{1}{x}\right) \\&=&-\tan{\psi}\left(\frac{1}{r\sin{\theta}\cos{\psi}}\right) \\\frac{\partial \psi}{\partial x} &=&-\tan{\psi}\left(\frac{1}{r\sin{\theta}\cos{\psi}}\right)\cos^2{\psi} \\&=&-\frac{\sin{\psi}}{\cancel{\cos{\psi}}}\left(\frac{1}{r\sin{\theta}\cancel{\cos{\psi}}}\right)\cancel{\cos^2{\psi}} \\&=&-\frac{\sin{\psi}}{r\sin{\theta}} \end{eqnarray}$$

\(\frac{\partial r}{\partial y}\)を求める

\(d\)の両辺を\(y\)の偏微分をとる. dの両辺をyの偏微分をとる. $$\begin{eqnarray} \frac{\partial }{\partial y}r^2&=&\frac{\partial }{\partial y}\left(x^2+y^2+z^2\right) \\2r\frac{\partial r}{\partial y}&=&2y \\\frac{\partial r}{\partial y} &=&\frac{\cancel{2}y}{\cancel{2}r}=\frac{y}{r}=\sin{\theta}\sin{\psi}\;\cdots\;bより \end{eqnarray}$$

\(\frac{\partial \theta}{\partial y}\)を求める

\(e\)の両辺を\(y\)の偏微分をとる. $$\begin{eqnarray} \frac{\partial }{\partial y}\cos{\theta}&=&\frac{\partial }{\partial y}\frac{z}{r} \\-\sin{\theta}\frac{\partial \theta}{\partial y}&=& z\frac{\partial }{\partial y}\frac{1}{r} \\&=&z\frac{\partial }{\partial r}\left(\frac{1}{r}\right)\frac{\partial r}{\partial y} \\&=&-\frac{z}{r^2}\frac{\partial r}{\partial y} \\&=&-\frac{z}{r^2}\;\sin{\theta}\sin{\psi}\;\cdots\;一つ前の\frac{\partial r}{\partial y}の結果 \\\frac{\partial \theta}{\partial y}&=&\left(\cancel{-}\frac{1}{\cancel{\sin{\theta}}}\right)\left(\cancel{-}\frac{z}{r^2}\cancel{\sin{\theta}}\sin{\psi}\right) =\frac{z}{r}\frac{\sin{\psi}}{r} \\&=&\frac{\cos{\theta}\sin{\psi}}{r}\;\cdots\;eより \end{eqnarray}$$

\(\frac{\partial \psi}{\partial y}\)を求める

\(f\)の両辺を\(y\)の偏微分をとる. $$\begin{eqnarray} \frac{\partial }{\partial y}\tan{\psi}&=&\frac{\partial }{\partial y}\frac{y}{x} \\\frac{1}{\cos^2{\psi}}\frac{\partial \psi}{\partial y} &=&\frac{1}{x} \\\frac{\partial \psi}{\partial y} &=&\left(\frac{1}{x}\right)\cos^2{\psi} \\&=&\left(\frac{1}{r\sin{\theta}\cancel{\cos{\psi}}}\right)\cos^\cancel{2}{\psi}\;\cdots\;aより \\&=&\frac{\cos{\psi}}{r\sin{\theta}} \end{eqnarray}$$

\(\frac{\partial r}{\partial z}\)を求める

\(d\)の両辺を\(z\)の偏微分をとる. $$\begin{eqnarray} \frac{\partial }{\partial z}r^2&=&\frac{\partial }{\partial z}\left(x^2+y^2+z^2\right) \\2r\frac{\partial r}{\partial z}&=&2z \\\frac{\partial r}{\partial z} &=&\frac{\cancel{2}z}{\cancel{2}r}=\frac{z}{r}=\cos{\theta}\;\cdots\;eより \end{eqnarray}$$

\(\frac{\partial \theta}{\partial z}\)を求める

\(e\)の両辺を\(z\)の偏微分をとる. $$\begin{eqnarray} \frac{\partial }{\partial z}\cos{\theta}&=&\frac{\partial }{\partial z}\frac{z}{r} \\-\sin{\theta}\frac{\partial \theta}{\partial z}&=& \frac{1}{r}+z\frac{\partial }{\partial z}\frac{1}{r} \\&=&\frac{1}{r}+z\frac{\partial }{\partial r}\left(\frac{1}{r}\right)\frac{\partial r}{\partial z} \\&=&\frac{1}{r}-\frac{z}{r^2}\frac{\partial r}{\partial z} \\&=&\frac{1}{r}-\frac{z}{r^2}\cos{\theta}\;\cdots\;一つ前の\frac{\partial r}{\partial z}の結果 \\\frac{\partial \theta}{\partial y} &=&\left(-\frac{1}{\sin{\theta}}\right)\left(\frac{1}{r}-\frac{z}{r^2}\cos{\theta}\right) \\&=&-\frac{1}{r\sin{\theta}}+\frac{z}{r}\frac{\cos{\theta}}{r\sin{\theta}} \\&=&-\frac{1}{r\sin{\theta}}+\frac{\cos^2{\theta}}{r\sin{\theta}}\;\cdots\;eより \\&=&-\frac{1-\cos^2{\theta}}{r\sin{\theta}} \\&=&-\frac{\sin^\cancel{2}{\theta}}{r\cancel{\sin{\theta}}} \\&=&-\frac{\sin{\theta}}{r} \end{eqnarray}$$

\(\frac{\partial \psi}{\partial z}\)を求める

\(f\)の両辺を\(z\)の偏微分をとる. $$\begin{eqnarray} \frac{\partial }{\partial z}\tan{\psi}&=&\frac{\partial }{\partial z}\frac{y}{x} \\\frac{1}{\cos^2{\psi}}\frac{\partial \psi}{\partial z}&=&0 \\\frac{\partial \psi}{\partial y}&=&0 \end{eqnarray}$$

\(\frac{\partial }{\partial x}, \frac{\partial }{\partial y}, \frac{\partial }{\partial z}\)を求める

$$\begin{eqnarray} \frac{\partial }{\partial x}&=& \frac{\partial r}{\partial x}\frac{\partial }{\partial r} +\frac{\partial \theta}{\partial x}\frac{\partial }{\partial \theta} +\frac{\partial \psi}{\partial x}\frac{\partial }{\partial \psi} \\&=&\sin{\theta}\cos{\psi}\frac{\partial }{\partial r} +\frac{\cos{\theta}\cos{\psi}}{r}\frac{\partial }{\partial \theta} -\frac{\sin{\psi}}{r\sin{\theta}}\frac{\partial }{\partial \psi} \\\; \frac{\partial }{\partial y}&=& \frac{\partial r}{\partial y}\frac{\partial }{\partial r} +\frac{\partial \theta}{\partial y}\frac{\partial }{\partial \theta} +\frac{\partial \psi}{\partial y}\frac{\partial }{\partial \psi} \\&=&\sin{\theta}\sin{\psi}\frac{\partial }{\partial r} +\frac{\cos{\theta}\sin{\psi}}{r}\frac{\partial }{\partial \theta} +\frac{\cos{\psi}}{r\sin{\theta}}\frac{\partial }{\partial \psi} \\\; \\\frac{\partial }{\partial z}&=& \frac{\partial r}{\partial z}\frac{\partial }{\partial r} +\frac{\partial \theta}{\partial z}\frac{\partial }{\partial \theta} +\frac{\partial \psi}{\partial z}\frac{\partial }{\partial \psi} \\&=&\cos{\theta}\frac{\partial }{\partial r} -\frac{\sin{\theta}}{r}\frac{\partial }{\partial \theta} +0\frac{\partial }{\partial \psi} \\&=&\cos{\theta}\frac{\partial }{\partial r} -\frac{\sin{\theta}}{r}\frac{\partial }{\partial \theta} \end{eqnarray}$$

\(\frac{\partial^2 }{\partial x^2}\)を求める

$$\begin{eqnarray} \frac{\partial^2 }{\partial x^2}&=& \frac{\partial }{\partial x}\frac{\partial }{\partial x} \\&=& \left( \sin{\theta}\cos{\psi}\frac{\partial }{\partial r} +\frac{\cos{\theta}\cos{\psi}}{r}\frac{\partial }{\partial \theta} -\frac{\sin{\psi}}{r\sin{\theta}}\frac{\partial }{\partial \psi} \right) \left( \sin{\theta}\cos{\psi}\frac{\partial }{\partial r} +\frac{\cos{\theta}\cos{\psi}}{r}\frac{\partial }{\partial \theta} -\frac{\sin{\psi}}{r\sin{\theta}}\frac{\partial }{\partial \psi} \right) \\&=&\sin{\theta}\cos{\psi} \color{red}{ \frac{\partial }{\partial r}\left( \sin{\theta}\cos{\psi}\frac{\partial }{\partial r} +\frac{\cos{\theta}\cos{\psi}}{r}\frac{\partial }{\partial \theta} -\frac{\sin{\psi}}{r\sin{\theta}}\frac{\partial }{\partial \psi} \right)} \\&&+\frac{\cos{\theta}\cos{\psi}}{r} \color{green}{ \frac{\partial }{\partial \theta}\left( \sin{\theta}\cos{\psi}\frac{\partial }{\partial r} +\frac{\cos{\theta}\cos{\psi}}{r}\frac{\partial }{\partial \theta} -\frac{\sin{\psi}}{r\sin{\theta}}\frac{\partial }{\partial \psi} \right) } \\&&-\frac{\sin{\psi}}{r\sin{\theta}} \color{blue}{ \frac{\partial }{\partial \psi}\left( \sin{\theta}\cos{\psi}\frac{\partial }{\partial r} +\frac{\cos{\theta}\cos{\psi}}{r}\frac{\partial }{\partial \theta} -\frac{\sin{\psi}}{r\sin{\theta}}\frac{\partial }{\partial \psi} \right)} \\&=&\sin{\theta}\cos{\psi}\cdot \color{red}{A_x}\color{black}{} +\frac{\cos{\theta}\cos{\psi}}{r}\cdot \color{green}{B_x}\color{black}{} -\frac{\sin{\psi}}{r\sin{\theta}}\cdot \color{blue}{C_x}\color{black}{} \end{eqnarray}$$
$$\begin{eqnarray} \\A_x&=& \frac{\partial }{\partial r}\left(\sin{\theta}\cos{\psi}\frac{\partial }{\partial r}\right) +\frac{\partial }{\partial r}\left(\frac{\cos{\theta}\cos{\psi}}{r}\frac{\partial }{\partial \theta}\right) -\frac{\partial }{\partial r}\left(\frac{\sin{\psi}}{r\sin{\theta}}\frac{\partial }{\partial \psi}\right) \\&=& \frac{\partial }{\partial r}\left(\sin{\theta}\cos{\psi}\right)\cdot\frac{\partial }{\partial r} +\sin{\theta}\cos{\psi}\cdot\frac{\partial }{\partial r}\left(\frac{\partial }{\partial r}\right) \\&&+\frac{\partial }{\partial r}\left(\frac{\cos{\theta}\cos{\psi}}{r}\right)\cdot\frac{\partial }{\partial \theta} +\frac{\cos{\theta}\cos{\psi}}{r}\cdot\frac{\partial }{\partial r}\left(\frac{\partial }{\partial \theta}\right) \\&&-\frac{\partial }{\partial r}\left(\frac{\sin{\psi}}{r\sin{\theta}}\right)\cdot\frac{\partial }{\partial \psi} -\frac{\sin{\psi}}{r\sin{\theta}}\cdot\frac{\partial }{\partial r}\left(\frac{\partial }{\partial \psi}\right) \\&=& \left(0\right)\frac{\partial }{\partial r} +\sin{\theta}\cos{\psi}\frac{\partial^2 }{\partial r^2} \\&&+\left(-\frac{\cos{\theta}\cos{\psi}}{r^2}\right)\frac{\partial }{\partial\theta} +\frac{\cos{\theta}\cos{\psi}}{r}\frac{\partial^2 }{\partial r \partial \theta} \\&&-\left(-\frac{\sin{\psi}}{r^2\sin{\theta}}\right)\cdot\frac{\partial }{\partial \psi} -\frac{\sin{\psi}}{r\sin{\theta}}\cdot\frac{\partial }{\partial r \partial \psi} \\&=& \sin{\theta}\cos{\psi}\frac{\partial^2 }{\partial r^2} -\frac{\cos{\theta}\cos{\psi}}{r^2}\frac{\partial }{\partial\theta} +\frac{\cos{\theta}\cos{\psi}}{r}\frac{\partial^2 }{\partial r \partial \theta} +\frac{\sin{\psi}}{r^2\sin{\theta}}\frac{\partial }{\partial \psi} -\frac{\sin{\psi}}{r\sin{\theta}}\frac{\partial^2 }{\partial r \partial \psi} \end{eqnarray}$$ $$\begin{eqnarray} \sin{\theta}\cos{\psi}\cdot A_x &=&\sin{\theta}\cos{\psi} \left\{ \sin{\theta}\cos{\psi}\frac{\partial^2 }{\partial r^2} -\frac{\cos{\theta}\cos{\psi}}{r^2}\frac{\partial }{\partial\theta} +\frac{\cos{\theta}\cos{\psi}}{r}\frac{\partial^2 }{\partial r \partial \theta} +\frac{\sin{\psi}}{r^2\sin{\theta}}\frac{\partial }{\partial \psi} -\frac{\sin{\psi}}{r\sin{\theta}}\frac{\partial^2 }{\partial r \partial \psi} \right\} \\&=& \sin^2{\theta}\cos^2{\psi}\frac{\partial^2 }{\partial r^2} -\frac{\cos{\theta}\sin{\theta}\cos^2{\psi}}{r^2}\frac{\partial }{\partial\theta} +\frac{\cos{\theta}\sin{\theta}\cos^2{\psi}}{r}\frac{\partial^2 }{\partial r \partial \theta} +\frac{\cancel{\sin{\theta}}\cos{\psi}\sin{\psi}}{r^2\cancel{\sin{\theta}}}\frac{\partial }{\partial \psi} -\frac{\cancel{\sin{\theta}}\cos{\psi}\sin{\psi}}{r\cancel{\sin{\theta}}}\frac{\partial^2 }{\partial r \partial \psi} \\&=& \sin^2{\theta}\cos^2{\psi}\frac{\partial^2 }{\partial r^2} -\frac{\cos{\theta}\sin{\theta}\cos^2{\psi}}{r^2}\frac{\partial }{\partial\theta} +\frac{\cos{\theta}\sin{\theta}\cos^2{\psi}}{r}\frac{\partial^2 }{\partial r \partial \theta} +\frac{\cos{\psi}\sin{\psi}}{r^2}\frac{\partial }{\partial \psi} -\frac{\cos{\psi}\sin{\psi}}{r}\frac{\partial^2 }{\partial r \partial \psi} \end{eqnarray}$$
$$\begin{eqnarray} \\B_x&=&\frac{\partial }{\partial \theta}\left(\sin{\theta}\cos{\psi}\frac{\partial }{\partial r}\right) +\frac{\partial }{\partial \theta}\left(\frac{\cos{\theta}\cos{\psi}}{r}\frac{\partial }{\partial \theta}\right) -\frac{\partial }{\partial \theta}\left(\frac{\sin{\psi}}{r\sin{\theta}}\frac{\partial }{\partial \psi}\right) \\&=& \frac{\partial }{\partial \theta}\left(\sin{\theta}\cos{\psi}\right)\cdot\frac{\partial }{\partial r} +\sin{\theta}\cos{\psi}\cdot\frac{\partial }{\partial \theta}\left(\frac{\partial }{\partial r}\right) \\&&+\frac{\partial }{\partial \theta}\left(\frac{\cos{\theta}\cos{\psi}}{r}\right) \cdot\frac{\partial}{\partial \theta} +\frac{\cos{\theta}\cos{\psi}}{r}\cdot\frac{\partial }{\partial \theta}\left(\frac{\partial }{\partial \theta}\right) \\&&-\frac{\partial }{\partial \theta}\left(\frac{\sin{\psi}}{r\sin{\theta}}\right) \cdot\frac{\partial }{\partial \psi} -\frac{\sin{\psi}}{r\sin{\theta}}\cdot\frac{\partial }{\partial \theta}\left(\frac{\partial }{\partial \psi}\right) \\&=& \left(\cos{\theta}\cos{\psi}\right)\frac{\partial }{\partial r} +\sin{\theta}\cos{\psi}\frac{\partial^2 }{\partial \theta \partial r} -\frac{\sin{\theta}\cos{\psi}}{r}\frac{\partial}{\partial \theta} +\frac{\cos{\theta}\cos{\psi}}{r}\frac{\partial^2 }{\partial \theta^2} +\frac{\cos{\theta}\sin{\psi}}{r\sin^2{\theta}}\frac{\partial }{\partial \psi} -\frac{\sin{\psi}}{r\sin{\theta}}\frac{\partial^2 }{\partial \theta \partial \psi} \end{eqnarray}$$ $$\begin{eqnarray} \frac{\cos{\theta}\cos{\psi}}{r}\cdot B_x &=&\frac{\cos{\theta}\cos{\psi}}{r}\left\{ \left(\cos{\theta}\cos{\psi}\right)\frac{\partial }{\partial r} +\sin{\theta}\cos{\psi}\frac{\partial^2 }{\partial \theta \partial r} -\frac{\sin{\theta}\cos{\psi}}{r}\frac{\partial}{\partial \theta} +\frac{\cos{\theta}\cos{\psi}}{r}\frac{\partial^2 }{\partial \theta^2} +\frac{\cos{\theta}\sin{\psi}}{r\sin^2{\theta}}\frac{\partial }{\partial \psi} -\frac{\sin{\psi}}{r\sin{\theta}}\frac{\partial^2 }{\partial \theta \partial \psi} \right\} \\&=&\frac{\cos^2{\theta}\cos^2{\psi}}{r}\frac{\partial }{\partial r} +\frac{\cos{\theta}\sin{\theta}\cos^2{\psi}}{r}\frac{\partial^2 }{\partial \theta \partial r} -\frac{\cos{\theta}\sin{\theta}\cos^2{\psi}}{r^2}\frac{\partial}{\partial \theta} +\frac{\cos^2{\theta}\cos^2{\psi}}{r^2}\frac{\partial^2 }{\partial \theta^2} +\frac{\cos^2{\theta}\cos{\psi}\sin{\psi}}{r^2\sin^2{\theta}}\frac{\partial }{\partial \psi} -\frac{\cos{\theta}\cos{\psi}\sin{\psi}}{r^2\sin{\theta}}\frac{\partial^2 }{\partial \theta \partial \psi} \end{eqnarray}$$
$$\begin{eqnarray} \\C_x&=& \frac{\partial }{\partial \psi}\left(\sin{\theta}\cos{\psi}\frac{\partial }{\partial r}\right) +\frac{\partial }{\partial \psi}\left(\frac{\cos{\theta}\cos{\psi}}{r}\frac{\partial }{\partial \theta}\right) -\frac{\partial }{\partial \psi}\left(\frac{\sin{\psi}}{r\sin{\theta}}\frac{\partial }{\partial \psi}\right) \\&=& \frac{\partial }{\partial \psi}\left(\sin{\theta}\cos{\psi}\right)\cdot\frac{\partial }{\partial r} +\sin{\theta}\cos{\psi}\cdot\frac{\partial }{\partial \psi}\left(\frac{\partial }{\partial r}\right) \\&&+\frac{\partial }{\partial \psi}\left(\frac{\cos{\theta}\cos{\psi}}{r}\right)\cdot\frac{\partial }{\partial \theta} +\frac{\cos{\theta}\cos{\psi}}{r}\cdot\frac{\partial }{\partial \psi}\left(\frac{\partial }{\partial \theta}\right) \\&&-\frac{\partial }{\partial \psi}\left(\frac{\sin{\psi}}{r\sin{\theta}}\right)\cdot\frac{\partial }{\partial \psi} -\frac{\sin{\psi}}{r\sin{\theta}}\cdot\frac{\partial }{\partial \psi}\left(\frac{\partial }{\partial \psi}\right) \\&=& \left(-\sin{\theta}\sin{\psi}\right)\frac{\partial }{\partial r} +\sin{\theta}\cos{\psi}\frac{\partial^2 }{\partial \psi\partial r} \\&&+\left(-\frac{\cos{\theta}\sin{\psi}}{r}\right)\frac{\partial }{\partial\theta} +\frac{\cos{\theta}\cos{\psi}}{r}\frac{\partial^2 }{\partial \psi \partial \theta} \\&&-\left(\frac{\cos{\psi}}{r\sin{\theta}}\right)\frac{\partial }{\partial\psi} -\frac{\sin{\psi}}{r\sin{\theta}}\cdot\frac{\partial^2 }{\partial \psi^2} \\&=& -\sin{\theta}\sin{\psi}\frac{\partial }{\partial r} +\sin{\theta}\cos{\psi}\frac{\partial^2 }{\partial \psi\partial r} -\frac{\cos{\theta}\sin{\psi}}{r}\frac{\partial }{\partial\theta} +\frac{\cos{\theta}\cos{\psi}}{r}\frac{\partial^2 }{\partial \psi \partial \theta} -\frac{\cos{\psi}}{r\sin{\theta}}\frac{\partial }{\partial\psi} -\frac{\sin{\psi}}{r\sin{\theta}}\frac{\partial^2 }{\partial \psi^2} \end{eqnarray}$$ $$\begin{eqnarray} -\frac{\sin{\psi}}{r\sin{\theta}}\cdot C_x &=&-\frac{\sin{\psi}}{r\sin{\theta}}\left\{ -\sin{\theta}\sin{\psi}\frac{\partial }{\partial r} +\sin{\theta}\cos{\psi}\frac{\partial^2 }{\partial \psi\partial r} -\frac{\cos{\theta}\sin{\psi}}{r}\frac{\partial }{\partial\theta} +\frac{\cos{\theta}\cos{\psi}}{r}\frac{\partial^2 }{\partial \psi \partial \theta} -\frac{\cos{\psi}}{r\sin{\theta}}\frac{\partial }{\partial\psi} -\frac{\sin{\psi}}{r\sin{\theta}}\frac{\partial^2 }{\partial \psi^2} \right\} \\&=&\frac{\cancel{\sin{\theta}}\sin^2{\psi}}{r\cancel{\sin{\theta}}}\frac{\partial }{\partial r} -\frac{\cancel{\sin{\theta}}\cos{\psi}\sin{\psi}}{r\cancel{\sin{\theta}}}\frac{\partial^2 }{\partial \psi\partial r} +\frac{\cos{\theta}\sin^2{\psi}}{r^2\sin{\theta}}\frac{\partial }{\partial\theta} -\frac{\cos{\theta}\cos{\psi}\sin{\psi}}{r^2\sin{\theta}}\frac{\partial^2 }{\partial \psi \partial \theta} +\frac{\cos{\psi}\sin{\psi}}{r^2\sin^2{\theta}}\frac{\partial }{\partial\psi} +\frac{\sin^2{\psi}}{r^2\sin^2{\theta}}\frac{\partial^2 }{\partial \psi^2} \\&=&\frac{\sin^2{\psi}}{r}\frac{\partial }{\partial r} -\frac{\cos{\psi}\sin{\psi}}{r}\frac{\partial^2 }{\partial \psi\partial r} +\frac{\cos{\theta}\sin^2{\psi}}{r^2\sin{\theta}}\frac{\partial }{\partial\theta} -\frac{\cos{\theta}\cos{\psi}\sin{\psi}}{r^2\sin{\theta}}\frac{\partial^2 }{\partial \psi \partial \theta} +\frac{\cos{\psi}\sin{\psi}}{r^2\sin^2{\theta}}\frac{\partial }{\partial\psi} +\frac{\sin^2{\psi}}{r^2\sin^2{\theta}}\frac{\partial^2 }{\partial \psi^2} \end{eqnarray}$$
$$\begin{eqnarray} \frac{\partial^2 }{\partial x^2}&=& \sin{\theta}\cos{\psi}\cdot A_x +\frac{\cos{\theta}\cos{\psi}}{r}\cdot B_x -\frac{\sin{\psi}}{r\sin{\theta}}\cdot C_x \\&=& \sin^2{\theta}\cos^2{\psi}\frac{\partial^2 }{\partial r^2} -\frac{\cos{\theta}\sin{\theta}\cos^2{\psi}}{r^2}\frac{\partial }{\partial\theta} +\frac{\cos{\theta}\sin{\theta}\cos^2{\psi}}{r}\frac{\partial^2 }{\partial r \partial \theta} +\frac{\cos{\psi}\sin{\psi}}{r^2}\frac{\partial }{\partial \psi} -\frac{\cos{\psi}\sin{\psi}}{r}\frac{\partial^2 }{\partial r\partial \psi} \\&&+\frac{\cos^2{\theta}\cos^2{\psi}}{r}\frac{\partial }{\partial r} +\frac{\cos{\theta}\sin{\theta}\cos^2{\psi}}{r}\frac{\partial^2 }{\partial \theta \partial r} -\frac{\cos{\theta}\sin{\theta}\cos^2{\psi}}{r^2}\frac{\partial}{\partial \theta} +\frac{\cos^2{\theta}\cos^2{\psi}}{r^2}\frac{\partial^2 }{\partial \theta^2} +\frac{\cos^2{\theta}\cos{\psi}\sin{\psi}}{r^2\sin^2{\theta}}\frac{\partial }{\partial \psi} -\frac{\cos{\theta}\cos{\psi}\sin{\psi}}{r^2\sin{\theta}}\frac{\partial^2 }{\partial \theta \partial \psi} \\&&+\frac{\sin^2{\psi}}{r}\frac{\partial }{\partial r} -\frac{\cos{\psi}\sin{\psi}}{r}\frac{\partial^2 }{\partial \psi\partial r} +\frac{\cos{\theta}\sin^2{\psi}}{r^2\sin{\theta}}\frac{\partial }{\partial\theta} -\frac{\cos{\theta}\cos{\psi}\sin{\psi}}{r^2\sin{\theta}}\frac{\partial^2 }{\partial \psi \partial \theta} +\frac{\cos{\psi}\sin{\psi}}{r^2\sin^2{\theta}}\frac{\partial }{\partial\psi} +\frac{\sin^2{\psi}}{r^2\sin^2{\theta}}\frac{\partial^2 }{\partial \psi^2} \\&=& \sin^2{\theta}\cos^2{\psi}\frac{\partial^2 }{\partial r^2} +\frac{\cos^2{\theta}\cos^2{\psi}}{r^2}\frac{\partial^2 }{\partial \theta^2} +\frac{\sin^2{\psi}}{r^2\sin^2{\theta}}\frac{\partial^2 }{\partial \psi^2} \\&&+\frac{\cos{\theta}\sin{\theta}\cos^2{\psi}}{r}\frac{\partial^2 }{\partial r \partial \theta} +\frac{\cos{\theta}\sin{\theta}\cos^2{\psi}}{r}\frac{\partial^2 }{\partial \theta \partial r} \\&&-\frac{\cos{\psi}\sin{\psi}}{r}\frac{\partial^2 }{\partial r\partial \psi} -\frac{\cos{\psi}\sin{\psi}}{r}\frac{\partial^2 }{\partial\psi\partial r} \\&&-\frac{\cos{\theta}\cos{\psi}\sin{\psi}}{r^2\sin{\theta}}\frac{\partial^2 }{\partial \theta \partial \psi} -\frac{\cos{\theta}\cos{\psi}\sin{\psi}}{r^2\sin{\theta}}\frac{\partial^2 }{\partial \psi \partial \theta} \\&& +\frac{\cos^2{\theta}\cos^2{\psi}}{r}\frac{\partial }{\partial r} +\frac{\sin^2{\psi}}{r}\frac{\partial }{\partial r} \\&& -\frac{\cos{\theta}\sin{\theta}\cos^2{\psi}}{r^2}\frac{\partial }{\partial\theta} -\frac{\cos{\theta}\sin{\theta}\cos^2{\psi}}{r^2}\frac{\partial}{\partial \theta} +\frac{\cos{\theta}\sin^2{\psi}}{r^2\sin{\theta}}\frac{\partial }{\partial\theta} \\&&+\frac{\cos{\psi}\sin{\psi}}{r^2}\frac{\partial }{\partial \psi} +\frac{\cos^2{\theta}\cos{\psi}\sin{\psi}}{r^2\sin^2{\theta}}\frac{\partial }{\partial \psi} +\frac{\cos{\psi}\sin{\psi}}{r^2\sin^2{\theta}}\frac{\partial }{\partial\psi} \\&=& \sin^2{\theta}\cos^2{\psi}\frac{\partial^2 }{\partial r^2} +\frac{\cos^2{\theta}\cos^2{\psi}}{r^2}\frac{\partial^2 }{\partial \theta^2} +\frac{\sin^2{\psi}}{r^2\sin^2{\theta}}\frac{\partial^2 }{\partial \psi^2} \\&&+2\frac{\cos{\theta}\sin{\theta}\cos^2{\psi}}{r} \frac{\partial^2}{\partial r \partial \theta} \;\cdots\;\frac{\partial^2 }{\partial r \partial \theta}=\frac{\partial^2 }{\partial \theta \partial r}を仮定 \\&&-2\frac{\cos{\psi}\sin{\psi}}{r}\frac{\partial^2 }{\partial r\partial \psi} \;\cdots\;\frac{\partial^2 }{\partial r \partial \psi}=\frac{\partial^2 }{\partial \psi \partial r}を仮定 \\&&-2\frac{\cos{\theta}\cos{\psi}\sin{\psi}}{r^2\sin{\theta}}\frac{\partial^2 }{\partial\theta\partial\psi} \;\cdots\;\frac{\partial^2 }{\partial\theta\partial\psi}=\frac{\partial^2 }{\partial\psi\partial\theta}を仮定 \\&&+\frac{\cos^2{\theta}\cos^2{\psi}+\sin^2{\psi}}{r}\frac{\partial }{\partial r} \\&& +\left( -2\frac{\cos{\theta}\sin{\theta}\cos^2{\psi}}{r^2} +\frac{\cos{\theta}\sin^2{\psi}}{r^2\sin{\theta}} \right)\frac{\partial }{\partial\theta} \\&&+\frac{\cos{\psi}\sin{\psi}}{r^2\sin^2{\theta}}\left( \sin^2{\theta} +\cos^2{\theta} +1 \right)\frac{\partial }{\partial\psi} \;\cdots\;\sin^2{\theta}+\cos^2{\theta}=1 \\&=& \sin^2{\theta}\cos^2{\psi}\frac{\partial^2 }{\partial r^2} +\frac{\cos^2{\theta}\cos^2{\psi}}{r^2}\frac{\partial^2 }{\partial \theta^2} +\frac{\sin^2{\psi}}{r^2\sin^2{\theta}}\frac{\partial^2 }{\partial \psi^2} \\&&+2\frac{\cos{\theta}\sin{\theta}\cos^2{\psi}}{r} \frac{\partial^2}{\partial r \partial \theta} -2\frac{\cos{\psi}\sin{\psi}}{r}\frac{\partial^2 }{\partial r\partial \psi} -2\frac{\cos{\theta}\cos{\psi}\sin{\psi}}{r^2\sin{\theta}}\frac{\partial^2 }{\partial\theta\partial\psi} \\&&+\frac{\cos^2{\theta}\cos^2{\psi}+\sin^2{\psi}}{r}\frac{\partial }{\partial r} +\left( -2\frac{\cos{\theta}\sin{\theta}\cos^2{\psi}}{r^2} +\frac{\cos{\theta}\sin^2{\psi}}{r^2\sin{\theta}} \right)\frac{\partial }{\partial\theta} +2\frac{\cos{\psi}\sin{\psi}}{r^2\sin^2{\theta}}\frac{\partial}{\partial\psi} \end{eqnarray}$$

\(\frac{\partial^2 }{\partial y^2}\)を求める

$$\begin{eqnarray} \frac{\partial^2 }{\partial y^2}&=& \frac{\partial }{\partial y}\frac{\partial }{\partial y} \\&=& \left( \sin{\theta}\sin{\psi}\frac{\partial }{\partial r} +\frac{\cos{\theta}\sin{\psi}}{r}\frac{\partial }{\partial \theta} +\frac{\cos{\psi}}{r\sin{\theta}}\frac{\partial }{\partial \psi} \right) \left( \sin{\theta}\sin{\psi}\frac{\partial }{\partial r} +\frac{\cos{\theta}\sin{\psi}}{r}\frac{\partial }{\partial \theta} +\frac{\cos{\psi}}{r\sin{\theta}}\frac{\partial }{\partial \psi} \right) \\&=& \sin{\theta}\sin{\psi}\frac{\partial }{\partial r} \color{red}{\left( \sin{\theta}\sin{\psi}\frac{\partial }{\partial r} +\frac{\cos{\theta}\sin{\psi}}{r}\frac{\partial }{\partial \theta} +\frac{\cos{\psi}}{r\sin{\theta}}\frac{\partial }{\partial \psi} \right)} \\&&+\frac{\cos{\theta}\sin{\psi}}{r} \color{green}{\frac{\partial }{\partial \theta}\left( \sin{\theta}\sin{\psi}\frac{\partial }{\partial r} +\frac{\cos{\theta}\sin{\psi}}{r}\frac{\partial }{\partial \theta} +\frac{\cos{\psi}}{r\sin{\theta}}\frac{\partial }{\partial \psi} \right)} \\&&+\frac{\cos{\psi}}{r\sin{\theta}} \color{blue}{\frac{\partial }{\partial \psi}\left( \sin{\theta}\sin{\psi}\frac{\partial }{\partial r} +\frac{\cos{\theta}\sin{\psi}}{r}\frac{\partial }{\partial \theta} +\frac{\cos{\psi}}{r\sin{\theta}}\frac{\partial }{\partial \psi} \right)} \\&=& \sin{\theta}\sin{\psi}\frac{\partial }{\partial r}\color{red}{A_y}\color{black}{} +\frac{\cos{\theta}\sin{\psi}}{r}\color{green}{B_y}\color{black}{} +\frac{\cos{\psi}}{r\sin{\theta}}\color{blue}{C_y}\color{black}{} \end{eqnarray}$$
$$\begin{eqnarray} A_y&=&\frac{\partial }{\partial r} \left( \sin{\theta}\sin{\psi}\frac{\partial }{\partial r} +\frac{\cos{\theta}\sin{\psi}}{r}\frac{\partial }{\partial \theta} +\frac{\cos{\psi}}{r\sin{\theta}}\frac{\partial }{\partial \psi} \right) \\&=&\frac{\partial }{\partial r}\left(\sin{\theta}\sin{\psi}\right)\cdot\frac{\partial }{\partial r} +\sin{\theta}\sin{\psi}\cdot\frac{\partial }{\partial r}\left(\frac{\partial }{\partial r}\right) \\&&+\frac{\partial }{\partial r}\left(\frac{\cos{\theta}\sin{\psi}}{r}\right) \cdot\frac{\partial }{\partial\theta} +\frac{\cos{\theta}\sin{\psi}}{r} \cdot \frac{\partial }{\partial r}\left( \frac{\partial }{\partial\theta} \right) \\&&+\frac{\partial }{\partial r}\left(\frac{\cos{\psi}}{r\sin{\theta}}\right)\cdot\frac{\partial }{\partial \psi} +\frac{\cos{\psi}}{r\sin{\theta}}\cdot\frac{\partial }{\partial r}\left(\frac{\partial }{\partial \psi}\right) \\&=&\left(0\right)\frac{\partial }{\partial r} +\sin{\theta}\sin{\psi}\frac{\partial^2 }{\partial r^2} \\&&+\left(-\frac{\cos{\theta}\sin{\psi}}{r^2}\right)\frac{\partial }{\partial \theta} +\frac{\cos{\theta}\sin{\psi}}{r}\frac{\partial^2 }{\partial r\partial\theta} \\&&+\left(-\frac{\cos{\psi}}{r^2\sin{\theta}}\right)\frac{\partial }{\partial\psi} +\frac{\cos{\psi}}{r\sin{\theta}}\frac{\partial^2 }{\partial r\partial\psi} \\&=&\sin{\theta}\sin{\psi}\frac{\partial^2 }{\partial r^2} -\frac{\cos{\theta}\sin{\psi}}{r^2}\frac{\partial }{\partial \theta} +\frac{\cos{\theta}\sin{\psi}}{r}\frac{\partial^2 }{\partial r\partial\theta} -\frac{\cos{\psi}}{r^2\sin{\theta}}\frac{\partial }{\partial\psi} +\frac{\cos{\psi}}{r\sin{\theta}}\frac{\partial^2 }{\partial r\partial\psi} \end{eqnarray}$$ $$\begin{eqnarray} \sin{\theta}\sin{\psi}\cdot A_y &=& \sin{\theta}\sin{\psi}\left( \sin{\theta}\sin{\psi}\frac{\partial^2 }{\partial r^2} -\frac{\cos{\theta}\sin{\psi}}{r^2}\frac{\partial }{\partial \theta} +\frac{\cos{\theta}\sin{\psi}}{r}\frac{\partial^2 }{\partial r\partial\theta} -\frac{\cos{\psi}}{r^2\sin{\theta}}\frac{\partial }{\partial\psi} +\frac{\cos{\psi}}{r\sin{\theta}}\frac{\partial^2 }{\partial r\partial\psi} \right) \\&=&\sin^2{\theta}\sin^2{\psi}\frac{\partial^2 }{\partial r^2} -\frac{\cos{\theta}\sin{\theta}\sin^2{\psi}}{r^2}\frac{\partial }{\partial \theta} +\frac{\cos{\theta}\sin{\theta}\sin^2{\psi}}{r}\frac{\partial^2 }{\partial r\partial\theta} -\frac{\cancel{\sin{\theta}}\cos{\psi}\sin{\psi}}{r^2\cancel{\sin{\theta}}}\frac{\partial }{\partial\psi} +\frac{\cancel{\sin{\theta}}\cos{\psi}\sin{\psi}}{r\cancel{\sin{\theta}}} \frac{\partial^2 }{\partial r\partial\psi} \\&=&\sin^2{\theta}\sin^2{\psi}\frac{\partial^2 }{\partial r^2} -\frac{\cos{\theta}\sin{\theta}\sin^2{\psi}}{r^2}\frac{\partial }{\partial \theta} +\frac{\cos{\theta}\sin{\theta}\sin^2{\psi}}{r}\frac{\partial^2 }{\partial r\partial\theta} -\frac{\cos{\psi}\sin{\psi}}{r^2}\frac{\partial }{\partial\psi} +\frac{\cos{\psi}\sin{\psi}}{r}\frac{\partial^2 }{\partial r\partial\psi} \end{eqnarray}$$
$$\begin{eqnarray} B_y&=&\frac{\partial }{\partial \theta}\left( \sin{\theta}\sin{\psi}\frac{\partial }{\partial r} +\frac{\cos{\theta}\sin{\psi}}{r}\frac{\partial }{\partial \theta} +\frac{\cos{\psi}}{r\sin{\theta}}\frac{\partial }{\partial \psi} \right) \\&=&\frac{\partial }{\partial \theta}\left(\sin{\theta}\sin{\psi}\right)\cdot\frac{\partial }{\partial r} +\sin{\theta}\sin{\psi}\cdot\frac{\partial }{\partial \theta}\left(\frac{\partial }{\partial r}\right) \\&&+\frac{\partial }{\partial \theta}\left(\frac{\cos{\theta}\sin{\psi}}{r}\right)\cdot\frac{\partial }{\partial \theta} +\frac{\cos{\theta}\sin{\psi}}{r} \cdot \frac{\partial }{\partial \theta}\left( \frac{\partial }{\partial\theta} \right) \\&&+\frac{\partial }{\partial \theta}\left(\frac{\cos{\psi}}{r\sin{\theta}}\right)\cdot\frac{\partial }{\partial \psi} +\frac{\cos{\psi}}{r\sin{\theta}}\cdot\frac{\partial }{\partial \theta}\left(\frac{\partial }{\partial \psi}\right) \\&=&\cos{\theta}\sin{\psi}\frac{\partial }{\partial r} +\sin{\theta}\sin{\psi}\frac{\partial^2 }{\partial \theta\partial r} -\frac{\sin{\theta}\sin{\psi}}{r}\frac{\partial}{\partial \theta} +\frac{\cos{\theta}\sin{\psi}}{r}\frac{\partial^2 }{\partial \theta^2} -\frac{\cos{\theta}\cos{\psi}}{r\sin^2{\theta}}\frac{\partial}{\partial\psi} +\frac{\cos{\psi}}{r\sin{\theta}}\frac{\partial^2 }{\partial \theta \partial\psi} \end{eqnarray}$$ $$\begin{eqnarray} \frac{\cos{\theta}\sin{\psi}}{r}\cdot B_y &=&\frac{\cos{\theta}\sin{\psi}}{r}\left( \cos{\theta}\sin{\psi}\frac{\partial }{\partial r} +\sin{\theta}\sin{\psi}\frac{\partial^2 }{\partial \theta\partial r} -\frac{\sin{\theta}\sin{\psi}}{r}\frac{\partial}{\partial \theta} +\frac{\cos{\theta}\sin{\psi}}{r}\frac{\partial^2 }{\partial \theta^2} -\frac{\cos{\theta}\cos{\psi}}{r\sin^2{\theta}}\frac{\partial}{\partial\psi} +\frac{\cos{\psi}}{r\sin{\theta}}\frac{\partial^2 }{\partial \theta \partial\psi} \right) \\&=& \frac{\cos^2{\theta}\sin^2{\psi}}{r}\frac{\partial }{\partial r} +\frac{\cos{\theta}\sin{\theta}\sin^2{\psi}}{r}\frac{\partial^2 }{\partial \theta\partial r} -\frac{\cos{\theta}\sin{\theta}\sin^2{\psi}}{r^2}\frac{\partial}{\partial \theta} +\frac{\cos^2{\theta}\sin^2{\psi}}{r^2}\frac{\partial^2 }{\partial \theta^2} -\frac{\cos^2{\theta}\cos{\psi}\sin{\psi}}{r^2\sin^2{\theta}}\frac{\partial}{\partial\psi} +\frac{\cos{\theta}\cos{\psi}\sin{\psi}}{r^2\sin{\theta}}\frac{\partial^2 }{\partial\theta\partial\psi} \end{eqnarray}$$
$$\begin{eqnarray} C_y&=&\frac{\partial }{\partial \psi}\left( \sin{\theta}\sin{\psi}\frac{\partial }{\partial r} +\frac{\cos{\theta}\sin{\psi}}{r}\frac{\partial }{\partial \theta} +\frac{\cos{\psi}}{r\sin{\theta}}\frac{\partial }{\partial \psi} \right) \\&=&\frac{\partial }{\partial \psi}\left(\sin{\theta}\sin{\psi}\right)\cdot\frac{\partial }{\partial r} +\sin{\theta}\sin{\psi}\cdot\frac{\partial }{\partial \psi}\left(\frac{\partial }{\partial r}\right) \\&&+\frac{\partial }{\partial \psi}\left(\frac{\cos{\theta}\sin{\psi}}{r}\right)\cdot\frac{\partial }{\partial \theta} +\frac{\cos{\theta}\sin{\psi}}{r} \cdot \frac{\partial }{\partial \psi}\left( \frac{\partial }{\partial\theta} \right) \\&&+\frac{\partial }{\partial \psi}\left(\frac{\cos{\psi}}{r\sin{\theta}}\right)\cdot\frac{\partial }{\partial \psi} +\frac{\cos{\psi}}{r\sin{\theta}}\cdot\frac{\partial }{\partial \psi}\left(\frac{\partial }{\partial \psi}\right) \\&=&\left(\sin{\theta}\cos{\psi}\right)\frac{\partial }{\partial r} +\sin{\theta}\sin{\psi}\frac{\partial^2 }{\partial \psi\partial r} \\&&+\left(\frac{\cos{\theta}\cos{\psi}}{r}\right)\frac{\partial}{\partial \theta} +\frac{\cos{\theta}\sin{\psi}}{r} \frac{\partial^2 }{\partial\psi\partial\theta} \\&&+\left(-\frac{\sin{\psi}}{r\sin{\theta}}\right)\frac{\partial}{\partial\psi} +\frac{\cos{\psi}}{r\sin{\theta}}\frac{\partial^2 }{\partial \psi^2} \\&=&\sin{\theta}\cos{\psi}\frac{\partial }{\partial r} +\sin{\theta}\sin{\psi}\frac{\partial^2 }{\partial \psi\partial r} +\frac{\cos{\theta}\cos{\psi}}{r}\frac{\partial}{\partial \theta} +\frac{\cos{\theta}\sin{\psi}}{r} \frac{\partial^2 }{\partial\psi\partial\theta} -\frac{\sin{\psi}}{r\sin{\theta}}\frac{\partial}{\partial\psi} +\frac{\cos{\psi}}{r\sin{\theta}}\frac{\partial^2 }{\partial \psi^2} \end{eqnarray}$$ $$\begin{eqnarray} \frac{\cos{\psi}}{r\sin{\theta}}\cdot C_y &=&\frac{\cos{\psi}}{r\sin{\theta}} \left( \sin{\theta}\cos{\psi}\frac{\partial }{\partial r} +\sin{\theta}\sin{\psi}\frac{\partial^2 }{\partial \psi\partial r} +\frac{\cos{\theta}\cos{\psi}}{r}\frac{\partial}{\partial \theta} +\frac{\cos{\theta}\sin{\psi}}{r} \frac{\partial^2 }{\partial\psi\partial\theta} -\frac{\sin{\psi}}{r\sin{\theta}}\frac{\partial}{\partial\psi} +\frac{\cos{\psi}}{r\sin{\theta}}\frac{\partial^2 }{\partial \psi^2} \right) \\&=& \frac{\cancel{\sin{\theta}}\cos^2{\psi}}{r\cancel{\sin{\theta}}}\frac{\partial }{\partial r} +\frac{\cancel{\sin{\theta}}\cos{\psi}\sin{\psi}}{r\cancel{\sin{\theta}}}\frac{\partial^2 }{\partial \psi\partial r} +\frac{\cos{\theta}\cos^2{\psi}}{r^2\sin{\theta}}\frac{\partial}{\partial \theta} +\frac{\cos{\theta}\cos{\psi}\sin{\psi}}{r^2\sin{\theta}} \frac{\partial^2}{\partial\psi\partial\theta} -\frac{\cos{\psi}\sin{\psi}}{r^2\sin^2{\theta}}\frac{\partial}{\partial\psi} +\frac{\cos^2{\psi}}{r^2\sin^2{\theta}}\frac{\partial^2 }{\partial \psi^2} \\&=& \frac{\cos^2{\psi}}{r}\frac{\partial }{\partial r} +\frac{\cos{\psi}\sin{\psi}}{r}\frac{\partial^2 }{\partial\psi\partial r} +\frac{\cos{\theta}\cos^2{\psi}}{r^2\sin{\theta}}\frac{\partial}{\partial \theta} +\frac{\cos{\theta}\cos{\psi}\sin{\psi}}{r^2\sin{\theta}} \frac{\partial^2}{\partial\psi\partial\theta} -\frac{\cos{\psi}\sin{\psi}}{r^2\sin^2{\theta}}\frac{\partial}{\partial\psi} +\frac{\cos^2{\psi}}{r^2\sin^2{\theta}}\frac{\partial^2 }{\partial \psi^2} \end{eqnarray}$$
$$\begin{eqnarray} \frac{\partial^2 }{\partial y^2} &=& \sin{\theta}\sin{\psi}\frac{\partial }{\partial r}A_y +\frac{\cos{\theta}\sin{\psi}}{r}B_y +\frac{\cos{\psi}}{r\sin{\theta}}C_y \\&=& \sin^2{\theta}\sin^2{\psi}\frac{\partial^2 }{\partial r^2} -\frac{\cos{\theta}\sin{\theta}\sin^2{\psi}}{r^2}\frac{\partial }{\partial \theta} +\frac{\cos{\theta}\sin{\theta}\sin^2{\psi}}{r}\frac{\partial^2 }{\partial r\partial\theta} -\frac{\cos{\psi}\sin{\psi}}{r^2}\frac{\partial }{\partial\psi} +\frac{\cos{\psi}\sin{\psi}}{r}\frac{\partial^2 }{\partial r\partial\psi} \\&&+\frac{\cos^2{\theta}\sin^2{\psi}}{r}\frac{\partial }{\partial r} +\frac{\cos{\theta}\sin{\theta}\sin^2{\psi}}{r}\frac{\partial^2 }{\partial \theta\partial r} -\frac{\cos{\theta}\sin{\theta}\sin^2{\psi}}{r^2}\frac{\partial}{\partial \theta} +\frac{\cos^2{\theta}\sin^2{\psi}}{r^2}\frac{\partial^2 }{\partial \theta^2} -\frac{\cos^2{\theta}\cos{\psi}\sin{\psi}}{r^2\sin^2{\theta}}\frac{\partial}{\partial\psi} +\frac{\cos{\theta}\cos{\psi}\sin{\psi}}{r^2\sin{\theta}}\frac{\partial^2 }{\partial\theta\partial\psi} \\&&+\frac{\cos^2{\psi}}{r}\frac{\partial }{\partial r} +\frac{\cos{\psi}\sin{\psi}}{r}\frac{\partial^2 }{\partial\psi\partial r} +\frac{\cos{\theta}\cos^2{\psi}}{r^2\sin{\theta}}\frac{\partial}{\partial \theta} +\frac{\cos{\theta}\cos{\psi}\sin{\psi}}{r^2\sin{\theta}} \frac{\partial^2}{\partial\psi\partial\theta} -\frac{\cos{\psi}\sin{\psi}}{r^2\sin^2{\theta}}\frac{\partial}{\partial\psi} +\frac{\cos^2{\psi}}{r^2\sin^2{\theta}}\frac{\partial^2 }{\partial \psi^2} \\&=& \sin^2{\theta}\sin^2{\psi}\frac{\partial^2 }{\partial r^2} +\frac{\cos^2{\theta}\sin^2{\psi}}{r^2}\frac{\partial^2 }{\partial \theta^2} +\frac{\cos^2{\psi}}{r^2\sin^2{\theta}}\frac{\partial^2 }{\partial \psi^2} \\&&+\frac{\cos{\theta}\sin{\theta}\sin^2{\psi}}{r}\frac{\partial^2 }{\partial r\partial\theta} +\frac{\cos{\theta}\sin{\theta}\sin^2{\psi}}{r}\frac{\partial^2 }{\partial \theta\partial r} \\&&+\frac{\cos{\psi}\sin{\psi}}{r}\frac{\partial^2 }{\partial r\partial\psi} +\frac{\cos{\psi}\sin{\psi}}{r}\frac{\partial^2 }{\partial\psi\partial r} \\&&+\frac{\cos{\theta}\cos{\psi}\sin{\psi}}{r^2\sin{\theta}}\frac{\partial^2 }{\partial\theta\partial\psi} +\frac{\cos{\theta}\cos{\psi}\sin{\psi}}{r^2\sin{\theta}} \frac{\partial^2}{\partial\psi\partial\theta} \\&& +\frac{\cos^2{\theta}\sin^2{\psi}}{r}\frac{\partial }{\partial r} +\frac{\cos^2{\psi}}{r}\frac{\partial }{\partial r} \\&&-\frac{\cos{\theta}\sin{\theta}\sin^2{\psi}}{r^2}\frac{\partial}{\partial \theta} -\frac{\cos{\theta}\sin{\theta}\sin^2{\psi}}{r^2}\frac{\partial}{\partial \theta} +\frac{\cos{\theta}\cos^2{\psi}}{r^2\sin{\theta}}\frac{\partial}{\partial \theta} \\&&-\frac{\cos{\psi}\sin{\psi}}{r^2}\frac{\partial }{\partial\psi} -\frac{\cos^2{\theta}\cos{\psi}\sin{\psi}}{r^2\sin^2{\theta}}\frac{\partial}{\partial\psi} -\frac{\cos{\psi}\sin{\psi}}{r^2\sin^2{\theta}}\frac{\partial}{\partial\psi} \\&=& \sin^2{\theta}\sin^2{\psi}\frac{\partial^2 }{\partial r^2} +\frac{\cos^2{\theta}\sin^2{\psi}}{r^2}\frac{\partial^2 }{\partial \theta^2} +\frac{\cos^2{\psi}}{r^2\sin^2{\theta}}\frac{\partial^2 }{\partial \psi^2} \\&&+2\frac{\cos{\theta}\sin{\theta}\sin^2{\psi}}{r}\frac{\partial^2 }{\partial r\partial\theta} \;\cdots\;\frac{\partial^2 }{\partial r \partial \theta}=\frac{\partial^2 }{\partial \theta \partial r}を仮定 \\&&+2\frac{\cos{\psi}\sin{\psi}}{r}\frac{\partial^2 }{\partial r\partial\psi} \;\cdots\;\frac{\partial^2 }{\partial r \partial \psi}=\frac{\partial^2 }{\partial \psi \partial r}を仮定 \\&&+2\frac{\cos{\theta}\cos{\psi}\sin{\psi}}{r^2\sin{\theta}}\frac{\partial^2 }{\partial\theta\partial\psi} \;\cdots\;\frac{\partial^2 }{\partial \theta \partial \psi}=\frac{\partial^2 }{\partial \psi \partial \theta}を仮定 \\&& +\frac{\cos^2{\theta}\sin^2{\psi}+\cos^2{\psi}}{r}\frac{\partial }{\partial r} \\&&+\left( -2\frac{\cos{\theta}\sin{\theta}\sin^2{\psi}}{r^2} +\frac{\cos{\theta}\cos^2{\psi}}{r^2\sin{\theta}} \right)\frac{\partial}{\partial \theta} \\&&-\frac{\cos{\psi}\sin{\psi}}{r^2\sin^2{\theta}}\left( \sin^2{\theta} +\cos^2{\theta} +1 \right)\frac{\partial}{\partial\psi} \;\cdots\;\sin^2{\theta}+\cos^2{\theta}=1 \\&=& \sin^2{\theta}\sin^2{\psi}\frac{\partial^2 }{\partial r^2} +\frac{\cos^2{\theta}\sin^2{\psi}}{r^2}\frac{\partial^2 }{\partial \theta^2} +\frac{\cos^2{\psi}}{r^2\sin^2{\theta}}\frac{\partial^2 }{\partial \psi^2} \\&&+2\frac{\cos{\theta}\sin{\theta}\sin^2{\psi}}{r}\frac{\partial^2 }{\partial r\partial\theta} +2\frac{\cos{\psi}\sin{\psi}}{r}\frac{\partial^2 }{\partial r\partial\psi} +2\frac{\cos{\theta}\cos{\psi}\sin{\psi}}{r^2\sin{\theta}}\frac{\partial^2 }{\partial\theta\partial\psi} \\&&+\frac{\cos^2{\theta}\sin^2{\psi}+\cos^2{\psi}}{r}\frac{\partial }{\partial r} +\left( -2\frac{\cos{\theta}\sin{\theta}\sin^2{\psi}}{r^2} +\frac{\cos{\theta}\cos^2{\psi}}{r^2\sin{\theta}} \right)\frac{\partial}{\partial \theta} -2\frac{\cos{\psi}\sin{\psi}}{r^2\sin^2{\theta}}\frac{\partial}{\partial\psi} \end{eqnarray}$$

\(\frac{\partial^2 }{\partial z^2}\)を求める

$$\begin{eqnarray} \frac{\partial^2 }{\partial z^2}&=& \frac{\partial }{\partial z}\frac{\partial }{\partial z} \\&=&\left( \cos{\theta}\frac{\partial }{\partial r} -\frac{\sin{\theta}}{r}\frac{\partial }{\partial \theta} \right) \left( \cos{\theta}\frac{\partial }{\partial r} -\frac{\sin{\theta}}{r}\frac{\partial }{\partial \theta} \right) \\&=& \cos{\theta}\color{red}{\frac{\partial }{\partial r} \left( \cos{\theta}\frac{\partial }{\partial r} -\frac{\sin{\theta}}{r}\frac{\partial }{\partial \theta} \right)}\color{black}{} -\frac{\sin{\theta}}{r}\color{green}{\frac{\partial }{\partial \theta} \left( \cos{\theta}\frac{\partial }{\partial r} -\frac{\sin{\theta}}{r}\frac{\partial }{\partial \theta} \right)} \\&=&\cos{\theta}\color{red}{A_z}\color{black}{}-\frac{\sin{\theta}}{r}\color{green}{B_z}\color{black}{} \end{eqnarray}$$
$$\begin{eqnarray} A_z&=&\frac{\partial }{\partial r} \left( \cos{\theta}\frac{\partial }{\partial r} -\frac{\sin{\theta}}{r}\frac{\partial }{\partial \theta} \right) \\&=& \frac{\partial }{\partial r} \left(\cos{\theta}\right)\cdot\frac{\partial }{\partial r} +\cos{\theta}\cdot\frac{\partial }{\partial r}\left(\frac{\partial }{\partial r}\right) \\&&+\frac{\partial }{\partial r}\left(-\frac{\sin{\theta}}{r}\right)\cdot\frac{\partial }{\partial \theta} -\frac{\sin{\theta}}{r}\cdot\frac{\partial }{\partial r}\left(\frac{\partial }{\partial \theta}\right) \\&=& \left(0\right)\frac{\partial }{\partial r} +\cos{\theta}\frac{\partial^2 }{\partial r^2} \\&&+\left(\frac{\sin{\theta}}{r^2}\right)\frac{\partial }{\partial \theta} -\frac{\sin{\theta}}{r}\frac{\partial^2 }{\partial r\partial \theta} \\&=& \cos{\theta}\frac{\partial^2 }{\partial r^2} +\frac{\sin{\theta}}{r^2}\frac{\partial }{\partial \theta} -\frac{\sin{\theta}}{r}\frac{\partial^2 }{\partial r\partial \theta} \end{eqnarray}$$ $$\begin{eqnarray} \cos{\theta}\cdot A_z&=&\cos{\theta}\left( \cos{\theta}\frac{\partial^2 }{\partial r^2} +\frac{\sin{\theta}}{r^2}\frac{\partial }{\partial \theta} -\frac{\sin{\theta}}{r}\frac{\partial^2 }{\partial r\partial \theta} \right) \\&=&\cos^2{\theta}\frac{\partial^2 }{\partial r^2} +\frac{\cos{\theta}\sin{\theta}}{r^2}\frac{\partial }{\partial \theta} -\frac{\cos{\theta}\sin{\theta}}{r}\frac{\partial^2 }{\partial r\partial \theta} \end{eqnarray}$$
$$\begin{eqnarray} B_z&=&\frac{\partial }{\partial \theta} \left( \cos{\theta}\frac{\partial }{\partial r} -\frac{\sin{\theta}}{r}\frac{\partial }{\partial \theta} \right) \\&=& \frac{\partial }{\partial \theta} \left(\cos{\theta}\right)\cdot\frac{\partial }{\partial r} +\cos{\theta}\cdot\frac{\partial }{\partial \theta}\left(\frac{\partial }{\partial r}\right) \\&&+\frac{\partial }{\partial \theta} \left(-\frac{\sin{\theta}}{r}\right)\cdot\frac{\partial }{\partial\theta} -\frac{\sin{\theta}}{r}\cdot\frac{\partial }{\partial \theta}\left(\frac{\partial }{\partial \theta}\right) \\&=& \left(-\sin{\theta}\right)\frac{\partial }{\partial r} +\cos{\theta}\frac{\partial^2 }{\partial \theta\partial r} \\&&+\left(-\frac{\cos{\theta}}{r}\right)\frac{\partial }{\partial\theta} -\frac{\sin{\theta}}{r}\frac{\partial^2 }{\partial \theta^2} \\&=& -\sin{\theta}\frac{\partial }{\partial r} +\cos{\theta}\frac{\partial^2 }{\partial \theta\partial r} -\frac{\cos{\theta}}{r}\frac{\partial }{\partial\theta} -\frac{\sin{\theta}}{r}\frac{\partial^2 }{\partial \theta^2} \end{eqnarray}$$ $$\begin{eqnarray} -\frac{\sin{\theta}}{r}B_z &=&-\frac{\sin{\theta}}{r}\left( -\sin{\theta}\frac{\partial }{\partial r} +\cos{\theta}\frac{\partial^2 }{\partial \theta\partial r} -\frac{\cos{\theta}}{r}\frac{\partial }{\partial\theta} -\frac{\sin{\theta}}{r}\frac{\partial^2 }{\partial \theta^2} \right) \\&=& \frac{\sin^2{\theta}}{r} \frac{\partial }{\partial r} -\frac{\cos{\theta}\sin{\theta}}{r} \frac{\partial^2 }{\partial \theta\partial r} +\frac{\cos{\theta}\sin{\theta}}{r^2} \frac{\partial }{\partial\theta} +\frac{\sin^2{\theta}}{r^2} \frac{\partial^2 }{\partial \theta^2} \end{eqnarray}$$
$$\begin{eqnarray} \frac{\partial^2 }{\partial z^2} &=& \cos{\theta}\cdot A_z-\frac{\sin{\theta}}{r}\cdot B_z \\&=& \cos^2{\theta}\frac{\partial^2 }{\partial r^2} +\frac{\cos{\theta}\sin{\theta}}{r^2}\frac{\partial }{\partial \theta} -\frac{\cos{\theta}\sin{\theta}}{r}\frac{\partial^2 }{\partial r\partial \theta} \\&&+\frac{\sin^2{\theta}}{r} \frac{\partial }{\partial r} -\frac{\cos{\theta}\sin{\theta}}{r} \frac{\partial^2 }{\partial \theta\partial r} +\frac{\cos{\theta}\sin{\theta}}{r^2} \frac{\partial }{\partial\theta} +\frac{\sin^2{\theta}}{r^2} \frac{\partial^2 }{\partial \theta^2} \\&=& \cos^2{\theta}\frac{\partial^2 }{\partial r^2} +\frac{\sin^2{\theta}}{r^2} \frac{\partial^2 }{\partial \theta^2} \\&&-\frac{\cos{\theta}\sin{\theta}}{r}\frac{\partial^2 }{\partial r\partial \theta} -\frac{\cos{\theta}\sin{\theta}}{r} \frac{\partial^2 }{\partial \theta\partial r} \\&&+\frac{\sin^2{\theta}}{r} \frac{\partial }{\partial r} \\&&+\frac{\cos{\theta}\sin{\theta}}{r^2} \frac{\partial }{\partial\theta} +\frac{\cos{\theta}\sin{\theta}}{r^2} \frac{\partial }{\partial\theta} \\&=& \cos^2{\theta}\frac{\partial^2 }{\partial r^2} +\frac{\sin^2{\theta}}{r^2}\frac{\partial^2 }{\partial \theta^2} \\&&-2\frac{\cos{\theta}\sin{\theta}}{r}\frac{\partial^2 }{\partial r\partial \theta} \;\cdots\;\frac{\partial^2 }{\partial r\partial \theta}=\frac{\partial^2 }{\partial \theta\partial r}を仮定 \\&&+\frac{\sin^2{\theta}}{r} \frac{\partial }{\partial r} \\&&+2\frac{\cos{\theta}\sin{\theta}}{r^2} \frac{\partial }{\partial\theta} \\&=& \cos^2{\theta}\frac{\partial^2 }{\partial r^2} +\frac{\sin^2{\theta}}{r^2}\frac{\partial^2 }{\partial \theta^2} -2\frac{\cos{\theta}\sin{\theta}}{r}\frac{\partial^2 }{\partial r\partial \theta} +\frac{\sin^2{\theta}}{r} \frac{\partial }{\partial r} +2\frac{\cos{\theta}\sin{\theta}}{r^2} \frac{\partial }{\partial\theta} \end{eqnarray}$$

\(\Delta\left(=\laplacian\right)\)を求める

$$\begin{eqnarray} \Delta&=& \frac{\partial^2 }{\partial x^2} +\frac{\partial^2 }{\partial y^2} +\frac{\partial^2 }{\partial z^2} \\&=& \sin^2{\theta}\cos^2{\psi}\frac{\partial^2 }{\partial r^2} +\frac{\cos^2{\theta}\cos^2{\psi}}{r^2}\frac{\partial^2 }{\partial \theta^2} +\frac{\sin^2{\psi}}{r^2\sin^2{\theta}}\frac{\partial^2 }{\partial \psi^2} +2\frac{\cos{\theta}\sin{\theta}\cos^2{\psi}}{r}\frac{\partial^2}{\partial r \partial \theta} -2\frac{\cos{\psi}\sin{\psi}}{r}\frac{\partial^2 }{\partial r\partial \psi} -2\frac{\cos{\theta}\cos{\psi}\sin{\psi}}{r^2\sin{\theta}}\frac{\partial^2 }{\partial\theta\partial\psi} +\frac{\cos^2{\theta}\cos^2{\psi}+\sin^2{\psi}}{r}\frac{\partial }{\partial r} +\left( -2\frac{\cos{\theta}\sin{\theta}\cos^2{\psi}}{r^2} +\frac{\cos{\theta}\sin^2{\psi}}{r^2\sin{\theta}} \right)\frac{\partial }{\partial\theta} +2\frac{\cos{\psi}\sin{\psi}}{r^2\sin^2{\theta}}\frac{\partial}{\partial\psi} \\&&+\sin^2{\theta}\sin^2{\psi}\frac{\partial^2 }{\partial r^2} +\frac{\cos^2{\theta}\sin^2{\psi}}{r^2}\frac{\partial^2 }{\partial \theta^2} +\frac{\cos^2{\psi}}{r^2\sin^2{\theta}}\frac{\partial^2 }{\partial \psi^2} +2\frac{\cos{\theta}\sin{\theta}\sin^2{\psi}}{r}\frac{\partial^2 }{\partial r\partial\theta} +2\frac{\cos{\psi}\sin{\psi}}{r}\frac{\partial^2 }{\partial r\partial\psi} +2\frac{\cos{\theta}\cos{\psi}\sin{\psi}}{r^2\sin{\theta}}\frac{\partial^2 }{\partial\theta\partial\psi} +\frac{\cos^2{\theta}\sin^2{\psi}+\cos^2{\psi}}{r}\frac{\partial }{\partial r} +\left( -2\frac{\cos{\theta}\sin{\theta}\sin^2{\psi}}{r^2} +\frac{\cos{\theta}\cos^2{\psi}}{r^2\sin{\theta}} \right)\frac{\partial}{\partial \theta} -2\frac{\cos{\psi}\sin{\psi}}{r^2\sin^2{\theta}}\frac{\partial}{\partial\psi} \\&&+\cos^2{\theta}\frac{\partial^2 }{\partial r^2} +\frac{\sin^2{\theta}}{r^2}\frac{\partial^2 }{\partial \theta^2} -2\frac{\cos{\theta}\sin{\theta}}{r}\frac{\partial^2 }{\partial r\partial \theta} +\frac{\sin^2{\theta}}{r} \frac{\partial }{\partial r} +2\frac{\cos{\theta}\sin{\theta}}{r^2} \frac{\partial }{\partial\theta} \\&=& \sin^2{\theta}\cos^2{\psi}\frac{\partial^2 }{\partial r^2} +\sin^2{\theta}\sin^2{\psi}\frac{\partial^2 }{\partial r^2} +\cos^2{\theta}\frac{\partial^2 }{\partial r^2} \\&& +\frac{\cos^2{\theta}\cos^2{\psi}}{r^2}\frac{\partial^2 }{\partial \theta^2} +\frac{\cos^2{\theta}\sin^2{\psi}}{r^2}\frac{\partial^2 }{\partial \theta^2} +\frac{\sin^2{\theta}}{r^2}\frac{\partial^2 }{\partial \theta^2} \\&& +\frac{\sin^2{\psi}}{r^2\sin^2{\theta}}\frac{\partial^2 }{\partial \psi^2} +\frac{\cos^2{\psi}}{r^2\sin^2{\theta}}\frac{\partial^2 }{\partial \psi^2} \\&& +2\frac{\cos{\theta}\sin{\theta}\cos^2{\psi}}{r}\frac{\partial^2}{\partial r\partial\theta} +2\frac{\cos{\theta}\sin{\theta}\sin^2{\psi}}{r}\frac{\partial^2}{\partial r\partial\theta} -2\frac{\cos{\theta}\sin{\theta}}{r}\frac{\partial^2}{\partial r\partial\theta} \\&& \cancel{-2\frac{\cos{\psi}\sin{\psi}}{r}\frac{\partial^2 }{\partial r\partial\psi}} \cancel{+2\frac{\cos{\psi}\sin{\psi}}{r}\frac{\partial^2 }{\partial r\partial\psi}} \\&& \cancel{ -2\frac{\cos{\theta}\cos{\psi}\sin{\psi}}{r^2\sin{\theta}}\frac{\partial^2 }{\partial\theta\partial\psi} } \cancel{ +2\frac{\cos{\theta}\cos{\psi}\sin{\psi}}{r^2\sin{\theta}}\frac{\partial^2 }{\partial\theta\partial\psi} } \\&& +\frac{\cos^2{\theta}\cos^2{\psi}+\sin^2{\psi}}{r}\frac{\partial }{\partial r} +\frac{\cos^2{\theta}\sin^2{\psi}+\cos^2{\psi}}{r}\frac{\partial }{\partial r} +\frac{\sin^2{\theta}}{r} \frac{\partial }{\partial r} \\&& +\left( -2\frac{\cos{\theta}\sin{\theta}\cos^2{\psi}}{r^2} +\frac{\cos{\theta}\sin^2{\psi}}{r^2\sin{\theta}} \right)\frac{\partial }{\partial\theta} +\left( -2\frac{\cos{\theta}\sin{\theta}\sin^2{\psi}}{r^2} +\frac{\cos{\theta}\cos^2{\psi}}{r^2\sin{\theta}} \right)\frac{\partial}{\partial \theta} +2\frac{\cos{\theta}\sin{\theta}}{r^2} \frac{\partial }{\partial\theta} \\&& \cancel{+2\frac{\cos{\psi}\sin{\psi}}{r^2\sin^2{\theta}}\frac{\partial}{\partial\psi}} \cancel{-2\frac{\cos{\psi}\sin{\psi}}{r^2\sin^2{\theta}}\frac{\partial}{\partial\psi}} \\&=& \sin^2{\theta}\left(\cos^2{\psi}+\sin^2{\psi}\right)\frac{\partial^2 }{\partial r^2} +\cos^2{\theta}\frac{\partial^2 }{\partial r^2} \;\cdots\;\cos^2{\psi}+\sin^2{\psi}=1 \\&& +\frac{\cos^2{\theta}}{r^2}\left( \cos^2{\psi} +\sin^2{\psi} \right)\frac{\partial^2 }{\partial \theta^2} +\frac{\sin^2{\theta}}{r^2}\frac{\partial^2 }{\partial \theta^2} \;\cdots\;\cos^2{\psi}+\sin^2{\psi}=1 \\&& +\frac{1}{r^2\sin^2{\theta}}\left(\sin^2{\psi}+\cos^2{\psi}\right)\frac{\partial^2 }{\partial \psi^2} \;\cdots\;\cos^2{\psi}+\sin^2{\psi}=1 \\&& +2\frac{\cos{\theta}\sin{\theta}}{r}\left( \cos^2{\psi}+\sin^2{\psi} \right)\frac{\partial^2}{\partial r\partial\theta} -2\frac{\cos{\theta}\sin{\theta}}{r}\frac{\partial^2}{\partial r\partial\theta} \;\cdots\;\cos^2{\psi}+\sin^2{\psi}=1 \\&& +\frac{ \cos^2{\theta}\left(\cos^2{\psi}+\sin^2{\psi}\right)+\left(\cos^2{\psi}+\sin^2{\psi}\right) +\sin^2{\theta} }{r}\frac{\partial }{\partial r} \;\cdots\;\cos^2{\psi}+\sin^2{\psi}=1 \\&& +\left\{ -2\frac{\cos{\theta}\sin{\theta}}{r^2}\left(\cos^2{\psi}+\sin^2{\psi}\right) +2\frac{\cos{\theta}\sin{\theta}}{r^2} +\frac{\cos{\theta}}{r^2\sin{\theta}}\left(\cos^2{\psi}+\sin^2{\psi}\right) \right\}\frac{\partial }{\partial\theta} \;\cdots\;\cos^2{\psi}+\sin^2{\psi}=1 \\&=& \left(\cos^2{\theta}+\sin^2{\theta}\right)\frac{\partial^2 }{\partial r^2} \\&& +\frac{1}{r^2}\left( \cos^2{\theta} +\sin^2{\theta} \right)\frac{\partial^2 }{\partial \theta^2} \;\cdots\;\cos^2{\theta}+\sin^2{\theta}=1 \\&& +\frac{1}{r^2\sin^2{\theta}}\frac{\partial^2 }{\partial \psi^2} \\&& \cancel{+2\frac{\cos{\theta}\sin{\theta}}{r}\frac{\partial^2}{\partial r\partial\theta}} \cancel{-2\frac{\cos{\theta}\sin{\theta}}{r}\frac{\partial^2}{\partial r\partial\theta}} \\&& +\frac{\cos^2{\theta}+\sin^2{\theta}+1}{r}\frac{\partial }{\partial r} \;\cdots\;\cos^2{\theta}+\sin^2{\theta}=1 \\&& +\left\{ \cancel{-2\frac{\cos{\theta}\sin{\theta}}{r^2}} \cancel{+2\frac{\cos{\theta}\sin{\theta}}{r^2}} +\frac{\cos{\theta}}{r^2\sin{\theta}} \right\}\frac{\partial }{\partial\theta} \\&=& \frac{\partial^2 }{\partial r^2} +\frac{1}{r^2}\frac{\partial^2 }{\partial \theta^2} +\frac{1}{r^2\sin^2{\theta}}\frac{\partial^2 }{\partial \psi^2} +\frac{2}{r}\frac{\partial }{\partial r} +\frac{\cos{\theta}}{r^2\sin{\theta}}\frac{\partial }{\partial\theta} \end{eqnarray}$$
$$\begin{eqnarray} \frac{1}{r^2}\frac{\partial }{\partial r}\left(r^2\frac{\partial }{\partial r}\right) &=& \frac{1}{r^2}\left\{ \frac{\partial }{\partial r}\left(r^2\right)\cdot\frac{\partial }{\partial r} +r^2\cdot\frac{\partial }{\partial r}\left(\frac{\partial }{\partial r}\right) \right\} \\&=& \frac{1}{r^2}\left\{ 2r\frac{\partial }{\partial r} +r^2\frac{\partial^2}{\partial r^2} \right\} \\&=& \frac{2}{r}\frac{\partial }{\partial r} +\frac{\cancel{r^2}}{\cancel{r^2}}\frac{\partial^2}{\partial r^2} \\&=& \frac{\partial^2}{\partial r^2} +\frac{2}{r}\frac{\partial }{\partial r} \end{eqnarray}$$
$$\begin{eqnarray} \frac{1}{r^2\sin{\theta}}\frac{\partial}{\partial \theta} \left( \sin{\theta}\frac{\partial }{\partial\theta} \right) &=& \frac{1}{r^2\sin{\theta}} \left\{ \frac{\partial }{\partial\theta}\left(\sin{\theta}\right)\cdot\frac{\partial }{\partial\theta} +\sin{\theta}\cdot\frac{\partial }{\partial\theta}\left(\frac{\partial }{\partial\theta}\right) \right\} \\&=& \frac{1}{r^2\sin{\theta}} \left\{ \cos{\theta}\frac{\partial }{\partial\theta} +\sin{\theta}\frac{\partial^2 }{\partial\theta^2} \right\} \\&=& \frac{\cos{\theta}}{r^2\sin{\theta}}\frac{\partial }{\partial\theta} +\frac{\cancel{\sin{\theta}}}{r^2\cancel{\sin{\theta}}}\frac{\partial^2 }{\partial\theta^2} \\&=& \frac{1}{r^2}\frac{\partial^2 }{\partial\theta^2} +\frac{\cos{\theta}}{r^2\sin{\theta}}\frac{\partial }{\partial\theta} \end{eqnarray}$$
$$\begin{eqnarray} \Delta&=& \frac{\partial^2 }{\partial r^2} +\frac{1}{r^2}\frac{\partial^2 }{\partial \theta^2} +\frac{1}{r^2\sin^2{\theta}}\frac{\partial^2 }{\partial \psi^2} +\frac{2}{r}\frac{\partial }{\partial r} +\frac{\cos{\theta}}{r^2\sin{\theta}}\frac{\partial }{\partial\theta} \\&=& \left\{ \frac{\partial^2 }{\partial r^2} +\frac{2}{r}\frac{\partial }{\partial r} \right\} +\left\{ \frac{1}{r^2}\frac{\partial^2 }{\partial \theta^2} +\frac{\cos{\theta}}{r^2\sin{\theta}}\frac{\partial }{\partial\theta} \right\} +\frac{1}{r^2\sin^2{\theta}}\frac{\partial^2 }{\partial \psi^2} \\&=& \frac{1}{r^2} \frac{\partial }{\partial r} \left( r^2\frac{\partial }{\partial r} \right) +\frac{1}{r^2\sin{\theta}}\frac{\partial}{\partial \theta} \left( \sin{\theta}\frac{\partial }{\partial\theta} \right) +\frac{1}{r^2\sin^2{\theta}}\frac{\partial^2 }{\partial \psi^2} \end{eqnarray}$$

cos(z)の微分

\(\cos{\left(z\right)}\)の微分

\(u+iv\)で表す

$$\begin{eqnarray} \cos{\left(z\right)} &=&\cos{\left(x\right)}\cos{\left(iy\right)}-\sin{\left(x\right)}\sin{\left(iy\right)} \\&=&\cos{\left(x\right)}\cosh{\left(y\right)}-\sin{\left(x\right)}i\sinh{\left(y\right)} \\&&\;\ldots\;\href{https://shikitenkai.blogspot.com/2021/07/cosi-x-sini-x-cos-sin.html}{\cos\left(iy\right)=i\cosh\left(y\right),\;\sin\left(iy\right)=i\sinh\left(y\right)} \\&=&\cos{\left(x\right)}\cosh{\left(y\right)}-i\sin{\left(x\right)}\sinh{\left(y\right)} \\&=&u(x,y)+iv(x,y) \end{eqnarray}$$ $$\left\{\begin{eqnarray} u(x,y)&=&\cos{\left(x\right)}\cosh{\left(y\right)} \\v(x,y)&=&-\sin{\left(x\right)}\sinh{\left(y\right)} \end{eqnarray}\;\ldots\;x,y\in\mathbb{R}\right.$$

\(u,v\)を\(x,y\)で偏微分する

$$\begin{eqnarray} \frac{\partial u(x,y)}{\partial x} &=&\frac{\partial}{\partial x}\cos{\left(x\right)}\cosh{\left(y\right)} \;\ldots\;x,y\in\mathbb{R} \\&=&\cosh{\left(y\right)}\frac{\partial}{\partial x}\cos{\left(x\right)} \\&=&\cosh{\left(y\right)}\left(-\sin{\left(x\right)}\right) \;\ldots\;\frac{\mathrm{d}}{\mathrm{d}\theta}\cos{\left(\theta\right)}=-\sin{\left(\theta\right)} \\&=&-\sin{\left(x\right)}\cosh{\left(y\right)} \end{eqnarray}$$ $$\begin{eqnarray} \frac{\partial u(x,y)}{\partial y} &=&\frac{\partial}{\partial y}\cos{\left(x\right)}\cosh{\left(y\right)} \;\ldots\;x,y\in\mathbb{R} \\&=&\cos{\left(x\right)}\frac{\partial}{\partial y}\cosh{\left(y\right)} \\&=&\cos{\left(x\right)}\sinh{\left(y\right)} \;\ldots\;\frac{\mathrm{d}}{\mathrm{d}\theta}\cosh{\left(\theta\right)}=\sinh{\left(\theta\right)} \end{eqnarray}$$ $$\begin{eqnarray} \frac{\partial v(x,y)}{\partial x} &=&\frac{\partial}{\partial x}\left(-\sin{\left(x\right)}\sinh{\left(y\right)}\right) \;\ldots\;x,y\in\mathbb{R} \\&=&-\sinh{\left(y\right)}\frac{\partial}{\partial x}\sin{\left(x\right)} \\&=&-\sinh{\left(y\right)}\cos{\left(x\right)} \;\ldots\;\frac{\mathrm{d}}{\mathrm{d}\theta}\sin{\left(\theta\right)}=\cos{\left(\theta\right)} \\&=&-\cos{\left(x\right)}\sinh{\left(y\right)} \end{eqnarray}$$ $$\begin{eqnarray} \frac{\partial v(x,y)}{\partial y} &=&\frac{\partial}{\partial y}\left(-\sin{\left(x\right)}\sinh{\left(y\right)}\right) \;\ldots\;x,y\in\mathbb{R} \\&=&-\sin{\left(x\right)}\frac{\partial}{\partial y}\sinh{\left(y\right)} \\&=&-\sin{\left(x\right)}\cosh{\left(y\right)} \;\ldots\;\frac{\mathrm{d}}{\mathrm{d}\theta}\sinh{\left(\theta\right)}=\cosh{\left(\theta\right)} \end{eqnarray}$$

コーシー・リーマンの関係式を満たす

$$\href{https://shikitenkai.blogspot.com/2021/07/blog-post_19.html}{\left\{ \begin{eqnarray} \frac{\partial u}{\partial x}&=&\frac{\partial v}{\partial y} \\\frac{\partial v}{\partial x}&=&-\frac{\partial u}{\partial y} \end{eqnarray} \right.}$$

実軸方向での微分

$$\begin{eqnarray} \frac{\mathrm{d}}{\mathrm{d}z}\cos{\left(z\right)} &=&\href{https://shikitenkai.blogspot.com/2021/07/blog-post_19.html}{\frac{\partial u(x,y)}{\partial x}+i\frac{\partial v(x,y)}{\partial x}} \\&=&-\sin{\left(x\right)}\cosh{\left(y\right)}+i\left(-\cos{\left(x\right)}\sinh{\left(y\right)}\right) \\&=&-\sin{\left(x\right)}\cosh{\left(y\right)}-i\cos{\left(x\right)}\sinh{\left(y\right)} \\&=&-\left(\sin{\left(x\right)}\cos{\left(iy\right)}+\cos{\left(x\right)}\sin{\left(iy\right)}\right) \\&&\;\ldots\;\href{https://shikitenkai.blogspot.com/2021/07/cosi-x-sini-x-cos-sin.html}{\cos\left(iy\right)=i\cosh\left(y\right),\;\sin\left(iy\right)=i\sinh\left(y\right)} \\&=&-\sin{\left(x+iy\right)} \\&=&-\sin{\left(z\right)} \end{eqnarray}$$

sin(z)の微分

\(\sin{\left(z\right)}\)の微分

\(u+iv\)で表す

$$\begin{eqnarray} \sin{\left(z\right)} &=&\sin{\left(x\right)}\cos{\left(iy\right)}+\cos{\left(x\right)}\sin{\left(iy\right)} \\&=&\sin{\left(x\right)}\cosh{\left(y\right)}+\cos{\left(x\right)}i\sinh{\left(y\right)} \\&&\;\ldots\;\href{https://shikitenkai.blogspot.com/2021/07/cosi-x-sini-x-cos-sin.html}{\cos\left(iy\right)=i\cosh\left(y\right),\;\sin\left(iy\right)=i\sinh\left(y\right)} \\&=&\sin{\left(x\right)}\cosh{\left(y\right)}+i\cos{\left(x\right)}\sinh{\left(y\right)} \\&=&u(x,y)+iv(x,y) \end{eqnarray}$$ $$\left\{\begin{eqnarray} u(x,y)&=&\sin{\left(x\right)}\cosh{\left(y\right)} \\v(x,y)&=&\cos{\left(x\right)}\sinh{\left(y\right)} \end{eqnarray}\;\ldots\;x,y\in\mathbb{R}\right.$$

\(u,v\)を\(x,y\)で偏微分する

$$\begin{eqnarray} \frac{\partial u(x,y)}{\partial x} &=&\frac{\partial}{\partial x}\sin{\left(x\right)}\cosh{\left(y\right)} \;\ldots\;x,y\in\mathbb{R} \\&=&\cosh{\left(y\right)}\frac{\partial}{\partial x}\sin{\left(x\right)} \\&=&\cosh{\left(y\right)}\cos{\left(x\right)} \;\ldots\;\frac{\mathrm{d}}{\mathrm{d}\theta}\sin{\left(\theta\right)}=\cos{\left(\theta\right)} \\&=&\cos{\left(x\right)}\cosh{\left(y\right)} \end{eqnarray}$$ $$\begin{eqnarray} \frac{\partial u(x,y)}{\partial y} &=&\frac{\partial}{\partial y}\sin{\left(x\right)}\cosh{\left(y\right)} \;\ldots\;x,y\in\mathbb{R} \\&=&\sin{\left(x\right)}\frac{\partial}{\partial y}\cosh{\left(y\right)} \\&=&\sin{\left(x\right)}\sinh{\left(y\right)} \;\ldots\;\frac{\mathrm{d}}{\mathrm{d}\theta}\cosh{\left(\theta\right)}=\sinh{\left(\theta\right)} \end{eqnarray}$$ $$\begin{eqnarray} \frac{\partial v(x,y)}{\partial x} &=&\frac{\partial}{\partial x}\cos{\left(x\right)}\sinh{\left(y\right)} \;\ldots\;x,y\in\mathbb{R} \\&=&\sinh{\left(y\right)}\frac{\partial}{\partial x}\cos{\left(x\right)} \\&=&\sinh{\left(y\right)}\left(-\sin{\left(x\right)}\right) \;\ldots\;\frac{\mathrm{d}}{\mathrm{d}\theta}\cos{\left(\theta\right)}=-\sin{\left(\theta\right)} \\&=&-\sin{\left(x\right)}\sinh{\left(y\right)} \end{eqnarray}$$ $$\begin{eqnarray} \frac{\partial v(x,y)}{\partial y} &=&\frac{\partial}{\partial y}\cos{\left(x\right)}\sinh{\left(y\right)} \;\ldots\;x,y\in\mathbb{R} \\&=&\cos{\left(x\right)}\frac{\partial}{\partial y}\sinh{\left(y\right)} \\&=&\cos{\left(x\right)}\cosh{\left(y\right)} \;\ldots\;\frac{\mathrm{d}}{\mathrm{d}\theta}\sinh{\left(\theta\right)}=\cosh{\left(\theta\right)} \end{eqnarray}$$

コーシー・リーマンの関係式を満たす

$$\href{https://shikitenkai.blogspot.com/2021/07/blog-post_19.html}{\left\{ \begin{eqnarray} \frac{\partial u}{\partial x}&=&\frac{\partial v}{\partial y} \\\frac{\partial v}{\partial x}&=&-\frac{\partial u}{\partial y} \end{eqnarray} \right.}$$

実軸方向での微分

$$\begin{eqnarray} \frac{\mathrm{d}}{\mathrm{d}z}\sin{\left(z\right)} &=&\href{https://shikitenkai.blogspot.com/2021/07/blog-post_19.html}{\frac{\partial u(x,y)}{\partial x}+i\frac{\partial v(x,y)}{\partial x}} \\&=&\cos{\left(x\right)}\cosh{\left(y\right)}+i\left(-\sin{\left(x\right)}\sinh{\left(y\right)}\right) \\&=&\cos{\left(x\right)}\cosh{\left(y\right)}-i\sin{\left(x\right)}\sinh{\left(y\right)} \\&=&\cos{\left(x\right)}\cos{\left(iy\right)}-\sin{\left(x\right)}\sin{\left(iy\right)} \\&&\;\ldots\;\href{https://shikitenkai.blogspot.com/2021/07/cosi-x-sini-x-cos-sin.html}{\cos\left(iy\right)=\cosh\left(y\right),\;\sin\left(iy\right)=i\sinh\left(y\right)} \\&=&\cos{\left(x+iy\right)} \\&=&\cos{\left(z\right)} \end{eqnarray}$$

log(z)の微分

\(\log{\left(z\right)}\)の微分

\(u+iv\)で表す

$$\begin{eqnarray} \log{\left(z\right)} &=&\log{\left(x+iy\right)} \;\ldots\;z=x+iy,\;z\in\mathbb{C},\;x,y\in\mathbb{R} \\&=&\log{\left( |z| e^{i\arg{\left(z\right)}} \right)} \\&&\;\ldots\;z=|z| e^{i\arg{\left(z\right)}},\;|z|=|x+iy|=\sqrt{x^2+y^2}は実数,\:\arg{\left(z\right)}は実数で多価(集合) \\&&\;\ldots\;\arg{\left(z\right)}=\mathrm{Arg}{\left(z\right)}+2n\pi,\;n\in\mathbb{Z} \\&&\;\ldots\;-\pi\lt\mathrm{Arg}{\left(z\right)}\leq\pi,\;\mathrm{Arg}{\left(z\right)}は実数で一価 \\&=&\log{\left(|z|\right)}+\log{\left(e^{i\arg{\left(z\right)}}\right)} \\&=&\log{\left(|z|\right)}+\log{\left(e^{i\left(\mathrm{Arg}{\left(z\right)}+2n\pi\right)}\right)} \\&=&\log{\left(|z|\right)}+i\left(\mathrm{Arg}{\left(z\right)}+2n\pi\right) \\&=&u(x,y)+iv(x,y)\;\ldots\;v(x,y)は実数で多価(集合) \end{eqnarray}$$ $$\left\{\begin{eqnarray} u(x,y)&=&\log{\left(\sqrt{x^2+y^2}\right)} \\v(x,y)&=&\mathrm{Arg}{\left(z\right)}+2n\pi=\begin{cases} \arctan{\left(\frac{y}{x}\right)}&+2n\pi & (x\gt0) \\\arctan{\left(\frac{y}{x}\right)}+\pi&+2n\pi & (x\lt0\;かつ\;y\geq0) \\\arctan{\left(\frac{y}{x}\right)}-\pi&+2n\pi & (x\lt0\;かつ\;y\lt0) \\\frac{\pi}{2}&+2n\pi & (x=0\;かつ\;y\gt0) \\-\frac{\pi}{2}&+2n\pi & (x=0\;かつ\;y\lt0) \\\mathrm{identerminate} && (x=0\;かつ\;y=0) \end{cases} \end{eqnarray}\;\ldots\;x,y\in\mathbb{R},\;n\in\mathbb{Z}\right.$$

\(u,v\)を\(x,y\)で偏微分する

$$\begin{eqnarray} \frac{\partial u(x,y)}{\partial x} &=&\frac{\partial}{\partial x}\log{\left(\sqrt{x^2+y^2}\right)} \\&=&\frac{\partial}{\partial f}\log{\left(f\right)}\frac{\partial f}{\partial x} \;\ldots\;f=\sqrt{x^2+y^2}=\left(x^2+y^2\right)^{\frac{1}{2}},\;f\in\mathbb{R} \\&=&\frac{\partial}{\partial f}\log{\left(f\right)} \frac{\partial f}{\partial g}\frac{\partial g}{\partial x} \;\ldots\;g=x^2+y^2,\;g\in\mathbb{R} \\&=&\frac{1}{f}\;\frac{1}{2}\left(g\right)^{-\frac{1}{2}}\;2x \\&=&\frac{1}{\sqrt{x^2+y^2}}\;\frac{1}{2\sqrt{x^2+y^2}}\;2x \\&=&\frac{x}{x^2+y^2} \end{eqnarray}$$ $$\begin{eqnarray} \frac{\partial u(x,y)}{\partial y} &=&\frac{\partial}{\partial y}\log{\left(\sqrt{x^2+y^2}\right)} \\&=&\frac{\partial}{\partial f}\log{\left(f\right)}\frac{\partial f}{\partial y} \;\ldots\;f=\sqrt{x^2+y^2}=\left(x^2+y^2\right)^{\frac{1}{2}},\;f\in\mathbb{R} \\&=&\frac{\partial}{\partial f}\log{\left(f\right)} \frac{\partial f}{\partial g}\frac{\partial g}{\partial y} \;\ldots\;g=x^2+y^2,\;g\in\mathbb{R} \\&=&\frac{1}{f}\;\frac{1}{2}\left(g\right)^{-\frac{1}{2}}\;2y \\&=&\frac{1}{\sqrt{x^2+y^2}}\;\frac{1}{2\sqrt{x^2+y^2}}\;2y \\&=&\frac{y}{x^2+y^2} \end{eqnarray}$$ $$\begin{eqnarray} \frac{\partial v(x,y)}{\partial x} &=&\frac{\partial}{\partial x}\mathrm{Arg}{\left(x+iy\right)}+2n\pi \\&=&\begin{cases} \frac{\partial}{\partial x}\left(\arctan{\left(\frac{y}{x}\right)}+2n\pi\right) & (x\gt0) \\\frac{\partial}{\partial x}\left(\arctan{\left(\frac{y}{x}\right)}+\pi+2n\pi\right) & (x\lt0\;かつ\;y\geq0) \\\frac{\partial}{\partial x}\left(\arctan{\left(\frac{y}{x}\right)}-\pi+2n\pi\right) & (x\lt0\;かつ\;y\lt0) \\\frac{\partial}{\partial x}\left(\frac{\pi}{2}+2n\pi\right) & (x=0\;かつ\;y\gt0) \\\frac{\partial}{\partial x}\left(-\frac{\pi}{2}+2n\pi\right) & (x=0\;かつ\;y\lt0) \\\mathrm{identerminate} & (x=0\;かつ\;y=0) \end{cases} \\&=&\begin{cases} \href{https://shikitenkai.blogspot.com/2021/07/blog-post_9.html}{\frac{-y}{x^2+y^2}} & (x\gt0) \\\href{https://shikitenkai.blogspot.com/2021/07/blog-post_9.html}{\frac{-y}{x^2+y^2}} & (x\lt0\;かつ\;y\geq0) \\\href{https://shikitenkai.blogspot.com/2021/07/blog-post_9.html}{\frac{-y}{x^2+y^2}} & (x\lt0\;かつ\;y\lt0) \\\href{https://shikitenkai.blogspot.com/2021/07/blog-post_9.html}{0} & (x=0\;かつ\;y\gt0) \\\href{https://shikitenkai.blogspot.com/2021/07/blog-post_9.html}{0} & (x=0\;かつ\;y\lt0) \\\mathrm{identerminate}& (x=0\;かつ\;y=0) \end{cases} \end{eqnarray}$$ $$\begin{eqnarray} \frac{\partial v(x,y)}{\partial y} &=&\frac{\partial}{\partial y}\mathrm{Arg}{\left(x+iy\right)}+2n\pi \\&=&\begin{cases} \frac{\partial}{\partial y}\left(\arctan{\left(\frac{y}{x}\right)}+2n\pi\right) & (x\gt0) \\\frac{\partial}{\partial y}\left(\arctan{\left(\frac{y}{x}\right)}+\pi+2n\pi\right) & (x\lt0\;かつ\;y\geq0) \\\frac{\partial}{\partial y}\left(\arctan{\left(\frac{y}{x}\right)}-\pi+2n\pi\right) & (x\lt0\;かつ\;y\lt0) \\\frac{\partial}{\partial y}\left(\frac{\pi}{2}+2n\pi\right) & (x=0\;かつ\;y\gt0) \\\frac{\partial}{\partial y}\left(-\frac{\pi}{2}+2n\pi\right) & (x=0\;かつ\;y\lt0) \\\mathrm{identerminate} & (x=0\;かつ\;y=0) \end{cases} \\&=&\begin{cases} \href{https://shikitenkai.blogspot.com/2021/07/blog-post_9.html}{\frac{x}{x^2+y^2}} & (x\gt0) \\\href{https://shikitenkai.blogspot.com/2021/07/blog-post_9.html}{\frac{x}{x^2+y^2}} & (x\lt0\;かつ\;y\geq0) \\\href{https://shikitenkai.blogspot.com/2021/07/blog-post_9.html}{\frac{x}{x^2+y^2}} & (x\lt0\;かつ\;y\lt0) \\\href{https://shikitenkai.blogspot.com/2021/07/blog-post_9.html}{0} & (x=0\;かつ\;y\gt0) \\\href{https://shikitenkai.blogspot.com/2021/07/blog-post_9.html}{0} & (x=0\;かつ\;y\lt0) \\\mathrm{identerminate}& (x=0\;かつ\;y=0) \end{cases} \end{eqnarray}$$

コーシー・リーマンの関係式を満たす

$$\href{https://shikitenkai.blogspot.com/2021/07/blog-post_19.html}{\left\{ \begin{eqnarray} \frac{\partial u}{\partial x}&=&\frac{\partial v}{\partial y} \\\frac{\partial v}{\partial x}&=&-\frac{\partial u}{\partial y} \end{eqnarray} \right.}$$

実軸方向での微分

$$\begin{eqnarray} \frac{\mathrm{d}}{\mathrm{d}z}\log{\left(z\right)} &=&\href{https://shikitenkai.blogspot.com/2021/07/blog-post_19.html}{\frac{\partial u(x,y)}{\partial x}+i\frac{\partial v(x,y)}{\partial x}} \\&=&\frac{x}{x^2+y^2}+i\frac{-y}{x^2+y^2} \\&=&\frac{x-iy}{x^2+y^2} \\&=&\frac{\cancel{x-iy}}{(x+iy)\cancel{(x-iy)}} \\&&\;\ldots\;(x+iy)(x-iy)=x^2\cancel{+ixy}\cancel{-ixy}-i^2y^2=x^2+y^2 \\&=&\frac{1}{x+iy} \\&=&\frac{1}{z}\;\ldots\;z=x+iy \end{eqnarray}$$

虚軸方向での微分

$$\begin{eqnarray} \frac{\mathrm{d}}{\mathrm{d}z}\log{\left(z\right)} &=&\href{https://shikitenkai.blogspot.com/2021/07/blog-post_19.html}{\frac{\partial v(x,y)}{\partial y}-i\frac{\partial u(x,y)}{\partial y}} \\&=&\frac{x}{x^2+y^2}-i\frac{y}{x^2+y^2} \\&=&\frac{x-iy}{x^2+y^2} \\&=&\frac{\cancel{x-iy}}{(x+iy)\cancel{(x-iy)}} \\&&\;\ldots\;(x+iy)(x-iy)=x^2\cancel{+ixy}\cancel{-ixy}-i^2y^2=x^2+y^2 \\&=&\frac{1}{x+iy} \\&=&\frac{1}{z}\;\ldots\;z=x+iy \end{eqnarray}$$

cot(z)の微分

\(u(x,y)\)を\(x\)で偏微分する

$$\begin{eqnarray} \frac{\partial u}{\partial x} &=&\frac{\partial}{\partial x}\href{https://shikitenkai.blogspot.com/2021/07/cotzuxyivxy.html}{\frac{\cos{\left(x\right)}\sin{\left(x\right)}} {\sin^2{\left(x\right)}+\sinh^2{\left(y\right)}}} \\&=&\frac{\sinh^2\left(y\right)(\cos^2\left(x\right)-\sin^2\left(x\right))-\sin^2\left(x\right)}{\left(\sin^2{\left(x\right)}+\sinh^2{\left(y\right)}\right)^2} \\&=&\frac{\cos^2\left(x\right)\sinh^2\left(y\right)-\sinh^2\left(y\right)\sin^2\left(x\right)-\sin^2\left(x\right)}{\left(\sin^2{\left(x\right)}+\sinh^2{\left(y\right)}\right)^2} \\&=&\frac{\cos^2\left(x\right)\sinh^2\left(y\right)-\sin^2\left(x\right)(1+\sinh^2\left(y\right))}{\left(\sin^2{\left(x\right)}+\sinh^2{\left(y\right)}\right)^2} \\&=&\frac{\cos^2\left(x\right)\sinh^2\left(y\right)-\sin^2\left(x\right)\cosh^2\left(y\right)}{\left(\sin^2{\left(x\right)}+\sinh^2{\left(y\right)}\right)^2} \end{eqnarray}$$

\(u(x,y)\)を\(y\)で偏微分する

$$\begin{eqnarray} \frac{\partial u}{\partial y} &=&\frac{\partial}{\partial y}\href{https://shikitenkai.blogspot.com/2021/07/cotzuxyivxy.html}{\frac{\cos{\left(x\right)}\sin{\left(x\right)}} {\sin^2{\left(x\right)}+\sinh^2{\left(y\right)}}} \\&=&-\frac{2\sin\left(x\right)\cos\left(x\right)\sinh\left(y\right)\cosh\left(y\right)}{\left(\sin^2{\left(x\right)}+\sinh^2{\left(y\right)}\right)^2} \end{eqnarray}$$

\(v(x,y)\)を\(x\)で偏微分する

$$\begin{eqnarray} \frac{\partial v}{\partial x} &=&\frac{\partial}{\partial x}\href{https://shikitenkai.blogspot.com/2021/07/cotzuxyivxy.html}{\frac{-\cosh{\left(y\right)}\sinh{\left(y\right)}} {\sin^2{\left(x\right)}+\sinh^2{\left(y\right)}}} \\&=&\frac{2\sin\left(x\right)\cos\left(x\right)\sinh\left(y\right)\cosh\left(y\right)}{\left(\sin^2{\left(x\right)}+\sinh^2{\left(y\right)}\right)^2} \end{eqnarray}$$

\(v(x,y)\)を\(y\)で偏微分する

$$\begin{eqnarray} \frac{\partial v}{\partial y} &=&\frac{\partial}{\partial y}\href{https://shikitenkai.blogspot.com/2021/07/cotzuxyivxy.html}{\frac{-\cosh{\left(y\right)}\sinh{\left(y\right)}} {\sin^2{\left(x\right)}+\sinh^2{\left(y\right)}}} \\&=&\frac{\cosh^2\left(y\right)(\sinh^2\left(y\right)-\sin^2\left(x\right))-\sinh^2\left(y\right)(\sinh^2\left(y\right)+\sin^2\left(x\right))}{\left(\sin^2{\left(x\right)}+\sinh^2{\left(y\right)}\right)^2} \\&=&\frac{\cosh^2\left(y\right)\sinh^2\left(y\right)-\cosh^2\left(y\right)\sin^2\left(x\right)-\sinh^2\left(y\right)\sinh^2\left(y\right)-\sinh^2\left(y\right)\sin^2\left(x\right)}{\left(\sin^2{\left(x\right)}+\sinh^2{\left(y\right)}\right)^2} \\&=&\frac{\sinh^2\left(y\right)(\cosh^2\left(y\right)-\sinh^2\left(y\right))-\cosh^2\left(y\right)\sin^2\left(x\right)-\sinh^2\left(y\right)\sin^2\left(x\right)}{\left(\sin^2{\left(x\right)}+\sinh^2{\left(y\right)}\right)^2} \\&=&\frac{\sinh^2\left(y\right)-\cosh^2\left(y\right)\sin^2\left(x\right)-\sinh^2\left(y\right)\sin^2\left(x\right)}{\left(\sin^2{\left(x\right)}+\sinh^2{\left(y\right)}\right)^2} \\&=&\frac{\sinh^2\left(y\right)(1-\sin^2\left(x\right))-\cosh^2\left(y\right)\sin^2\left(x\right)}{\left(\sin^2{\left(x\right)}+\sinh^2{\left(y\right)}\right)^2} \\&=&\frac{\cos^2\left(x\right)\sinh^2\left(y\right)-\sin^2\left(x\right)\cosh^2\left(y\right)}{\left(\sin^2{\left(x\right)}+\sinh^2{\left(y\right)}\right)^2} \end{eqnarray}$$

コーシー・リーマンの関係式を満たす

$$\href{https://shikitenkai.blogspot.com/2021/07/blog-post_19.html}{ \left\{ \begin{eqnarray} \frac{\partial u}{\partial x}&=&\frac{\partial v}{\partial y} \\\frac{\partial u}{\partial y}&=&-\frac{\partial v}{\partial x} \end{eqnarray} \right. }$$

実軸(x)方向の微分

$$\begin{eqnarray} \frac{\mathrm{d}}{\mathrm{d} z}\cot{}&=&\href{https://shikitenkai.blogspot.com/2021/07/blog-post_19.html}{\frac{\partial u(x,y)}{\partial x}+i\frac{\partial v(x,y)}{\partial x}} \\&=&\frac{\cos^2\left(x\right)\sinh^2\left(y\right)-\sin^2\left(x\right)\cosh^2\left(y\right)}{\left(\sin^2{\left(x\right)}+\sinh^2{\left(y\right)}\right)^2} +i\frac{2\sin\left(x\right)\cos\left(x\right)\sinh\left(y\right)\cosh\left(y\right)}{\left(\sin^2{\left(x\right)}+\sinh^2{\left(y\right)}\right)^2} \\&=&\frac{\left(\cos\left(x\right)\sinh\left(y\right)+i\sin\left(x\right)\cosh\left(y\right)\right)^2}{\left(\sin^2{\left(x\right)}+\sinh^2{\left(y\right)}\right)^2} \\&=&\frac{\left(\cos\left(x\right)\sinh\left(y\right)+i\sin\left(x\right)\cosh\left(y\right)\right)^2}{\left(\sin^2{\left(x\right)}+\sinh^2{\left(y\right)}\right)^2} \\&=&\frac{\left(\cos\left(x\right)\sinh\left(y\right)+i\sin\left(x\right)\cosh\left(y\right)\right)^2}{\left(\sin^2{\left(x\right)}+\sinh^2{\left(y\right)}\right)^2} \\&=&\frac{\left(\cos\left(x\right)\frac{1}{i}\sin\left(iy\right)+i\sin\left(x\right)\cos\left(iy\right)\right)^2} {\left(\sin^2{\left(x\right)}+\left(\frac{1}{i}\sin\left(iy\right)\right)^2\right)^2} \;\ldots\;\cos\left(iy\right)=i\cosh\left(y\right),\;\sin\left(iy\right)=i\sinh\left(y\right),\;\sinh\left(y\right)=\frac{1}{i}\sin\left(iy\right) \\&=&\frac{i^2}{i^2}\frac{\left(\cos\left(x\right)\frac{1}{i}\sin\left(iy\right)+i\sin\left(x\right)\cos\left(iy\right)\right)^2} {\left(\sin^2{\left(x\right)}+\left(\frac{1}{i}\right)^2\left(\sin\left(iy\right)\right)^2\right)^2} \\&=&\frac{1}{i^2}\frac{\left(i\left(\cos\left(x\right)\frac{1}{i}\sin\left(iy\right)+i\sin\left(x\right)\cos\left(iy\right)\right)\right)^2} {\left(\sin^2{\left(x\right)}-\sin^2\left(iy\right)\right)^2} \\&=&\frac{1}{-1}\frac{\left(\cos\left(x\right)\sin\left(iy\right)-\sin\left(x\right)\cos\left(iy\right)\right)^2} {\left(\sin^2{\left(x\right)}-\sin^2\left(iy\right)\right)^2} \\&=&-\frac{\left(-\left(-\cos\left(x\right)\sin\left(iy\right)+\sin\left(x\right)\cos\left(iy\right)\right)\right)^2} {\left(\sin^2{\left(x\right)}-\sin^2\left(iy\right)\right)^2} \\&=&-\frac{\left(-\sin(x-iy)\right)^2} {\left(\sin{\left(x+iy\right)}\sin{\left(x-iy\right)}\right)^2} \\&&\;\ldots\;\sin^2{\left(x\right)}-\sin^2\left(iy\right) \\&&\;\ldots\;=\sin^2{\left(x\right)}-\sin^2\left(iy\right)\color{red}{-\sin^2{\left(x\right)}\sin^2\left(iy\right)+\sin^2{\left(x\right)}\sin^2\left(iy\right)} \\&&\;\ldots\;=\sin^2{\left(x\right)}\left(1-\sin^2\left(iy\right)\right)-\sin^2{\left(iy\right)}\left(1-\sin^2\left(x\right)\right) \\&&\;\ldots\;=\sin^2{\left(x\right)}\cos^2\left(iy\right)-\sin^2{\left(iy\right)}\cos^2{\left(x\right)} \\&&\;\ldots\;=\left\{\sin{\left(x\right)}\cos\left(iy\right)+\sin{\left(iy\right)}\cos{\left(x\right)}\right\} \left\{\sin{\left(x\right)}\cos\left(iy\right)-\sin{\left(iy\right)}\cos{\left(x\right)}\right\} \\&&\;\ldots\;=\sin{\left(x+iy\right)}\sin{\left(x-iy\right)} \\&=&-\frac{\cancel{\sin^2(x-iy)}} {\sin^2{\left(x+iy\right)}\cancel{\sin^2{\left(x-iy\right)}}} \\&=&\frac{-1}{\sin^2{\left(x+iy\right)}} \\&=&\frac{-1}{\sin^2{\left(z\right)}} \end{eqnarray}$$

wzの微分

\(wz\)の微分

\(u+iv\)で表す

$$\begin{eqnarray} wz&=&(a+ib)(x+iy)\;\ldots\;a,b,x,y\in\mathbb{R},\;w,z\in\mathbb{C} \\&=&ax-by+i(ay+bx) \\&=&u(x,y)+iv(x,y) \end{eqnarray}$$

\(u,v\)を\(x,y\)で偏微分する

$$\begin{eqnarray} \frac{\partial u(x,y)}{\partial x}&=&\frac{\partial }{\partial x}(ax-by) \\&=&a \\\frac{\partial u(x,y)}{\partial y}&=&\frac{\partial }{\partial y}(ax-by) \\&=&-b \\\frac{\partial v(x,y)}{\partial x}&=&\frac{\partial }{\partial x}(ay+bx) \\&=&b \\\frac{\partial v(x,y)}{\partial y}&=&\frac{\partial }{\partial y}(ay+bx) \\&=&a \end{eqnarray}$$

コーシー・リーマンの関係式を満たす

$$\href{https://shikitenkai.blogspot.com/2021/07/blog-post_19.html}{ \left\{ \begin{eqnarray} \frac{\partial u}{\partial x}&=&\frac{\partial v}{\partial y} \\\frac{\partial u}{\partial y}&=&-\frac{\partial v}{\partial x} \end{eqnarray} \right. }$$

実軸(x)方向の微分

$$\begin{eqnarray} \frac{\mathrm{d}}{\mathrm{d} z}wz&=&\href{https://shikitenkai.blogspot.com/2021/07/blog-post_19.html}{\frac{\partial u(x,y)}{\partial x}+i\frac{\partial v(x,y)}{\partial x}} \\&=&a+ib \\&=&w \end{eqnarray}$$

虚軸(y)方向の微分

$$\begin{eqnarray} \frac{\mathrm{d}}{\mathrm{d} z}wz&=&\href{https://shikitenkai.blogspot.com/2021/07/blog-post_19.html}{\frac{\partial v(x,y)}{\partial y}-i\frac{\partial u(x,y)}{\partial y}} \\&=&a-i(-b) \\&=&a+ib \\&=&w \end{eqnarray}$$

azの微分

\(az\)の微分

\(u+iv\)で表す

$$\begin{eqnarray} az&=&a(x+iy)\;\ldots\;a,x,y\in\mathbb{R},\;z\in\mathbb{C} \\&=&ax+iay \\&=&u(x,y)+iv(x,y) \end{eqnarray}$$ $$\left\{ \begin{eqnarray} u(x,y)&=&ax \\v(x,y)&=&ay \end{eqnarray} \right.$$

\(u,v\)を\(x,y\)で偏微分する

$$\begin{eqnarray} \frac{\partial u(x,y)}{\partial x}&=&\frac{\partial }{\partial x}ax \\&=&a \\\frac{\partial u(x,y)}{\partial y}&=&\frac{\partial }{\partial y}ax \\&=&0 \\\frac{\partial v(x,y)}{\partial x}&=&\frac{\partial }{\partial x}ay \\&=&0 \\\frac{\partial v(x,y)}{\partial y}&=&\frac{\partial }{\partial y}ay \\&=&a \end{eqnarray}$$

コーシー・リーマンの関係式を満たす

$$\href{https://shikitenkai.blogspot.com/2021/07/blog-post_19.html}{ \left\{ \begin{eqnarray} \frac{\partial u}{\partial x}&=&\frac{\partial v}{\partial y} \\\frac{\partial u}{\partial y}&=&-\frac{\partial v}{\partial x} \end{eqnarray} \right. }$$

実軸方向での微分

\begin{eqnarray} \frac{\mathrm{d}}{\mathrm{d} z}az&=&\href{https://shikitenkai.blogspot.com/2021/07/blog-post_19.html}{\frac{\partial u(x,y)}{\partial x}+i\frac{\partial v(x,y)}{\partial x}} \\&=&a+i0 \\&=&a \end{eqnarray}

虚軸方向での微分

\begin{eqnarray} \frac{\mathrm{d}}{\mathrm{d} z}az&=&\href{https://shikitenkai.blogspot.com/2021/07/blog-post_19.html}{\frac{\partial v(x,y)}{\partial y}-i\frac{\partial u(x,y)}{\partial y}} \\&=&a-i0 \\&=&a \end{eqnarray}

コーシー・リーマンの関係式

コーシー・リーマンの関係式

複素平面の実軸方向の微分(偏微分)

$$\begin{eqnarray} \lim_{\Delta z\rightarrow0}\frac{f(z_0+\Delta z)-f(z_0)}{\Delta z} &=& \lim_{\Delta x\rightarrow0}\frac{\left\{u\left(x_0+\Delta x, y_0\right)+iv\left(x_0+\Delta x, y_0\right)\right\} -\left\{u\left(x_0, y_0\right)+iv\left(x_0, y_0\right)\right\}}{\Delta x} \;\ldots\;z_0,\Delta zin\mathbb{C},\;x_0,y_0,\Delta x\in\mathbb{R} \\&=& \lim_{\Delta x\rightarrow0}\left\{ \frac{ u\left(x_0+\Delta x, y_0\right) -u\left(x_0, y_0\right) }{\Delta x} +i\frac{ v\left(x_0+\Delta x, y_0\right) -v\left(x_0, y_0\right) }{\Delta x} \right\} \\&=&\frac{\partial u\left(x_0, y_0\right)}{\partial x}+i\frac{\partial v\left(x_0, y_0\right)}{\partial x} \end{eqnarray}$$

複素平面の虚軸方向の微分(偏微分)

$$\begin{eqnarray} \lim_{\Delta z\rightarrow0}\frac{f(z_0+\Delta z)-f(z_0)}{\Delta z} &=& \lim_{\Delta y\rightarrow0}\frac{\left\{u\left(x_0, y_0+\Delta y\right)+iv\left(x_0, y_0+\Delta y\right)\right\} -\left\{u\left(x_0, y_0\right)+iv\left(x_0, y_0\right)\right\}}{i\Delta y} \;\ldots\;z_0,\Delta zin\mathbb{C},\;x_0,y_0,\Delta y\in\mathbb{R} \\&=& \lim_{\Delta y\rightarrow0}\left\{ \frac{ u\left(x_0, y_0+\Delta y\right) -u\left(x_0, y_0\right) }{i\Delta y} +i\frac{ v\left(x_0, y_0+\Delta y\right) -v\left(x_0, y_0\right) }{i\Delta y} \right\} \\&=&\frac{1}{i}\frac{\partial u\left(x_0, y_0\right)}{\partial y}+\frac{i}{i}\frac{\partial v\left(x_0, y_0\right)}{\partial y} \\&=&\frac{i}{i}\frac{1}{i}\frac{\partial u\left(x_0, y_0\right)}{\partial y}+\frac{\partial v\left(x_0, y_0\right)}{\partial y} \\&=&\frac{i}{-1}\frac{\partial u\left(x_0, y_0\right)}{\partial y}+\frac{\partial v\left(x_0, y_0\right)}{\partial y} \\&=&-i\frac{\partial u\left(x_0, y_0\right)}{\partial y}+\frac{\partial v\left(x_0, y_0\right)}{\partial y} \\&=&\frac{\partial v\left(x_0, y_0\right)}{\partial y}+i\left\{-\frac{\partial u\left(x_0, y_0\right)}{\partial y}\right\} \end{eqnarray}$$

複素平面の各軸微分結果の実部同士,虚部同士が等しくなる場合という関係

$$\left\{ \begin{eqnarray} \frac{\partial u}{\partial x}&=&\frac{\partial v}{\partial y} \\\frac{\partial v}{\partial x}&=&-\frac{\partial u}{\partial y} \end{eqnarray} \right.$$

偏角の微分

$$\begin{eqnarray} z&=&x+iy\;\ldots\;z\in\mathbb{Z},\;x,y\in\mathbb{R} \\&=&re^{i\theta}\;\ldots\;r,\theta\in\mathbb{R},\;r\geq0,\;-\pi\lt\theta\leq\pi \\r&=&|z|=\sqrt{x^2+y^2} \\\arg{\left(z\right)}&=&\theta+2n\pi\;\left(n\in\mathbb{Z}\right) \\&=&\mathrm{Arg}{\left(z\right)}+2n\pi\;\left(n\in\mathbb{Z}\right) \end{eqnarray}$$ $$\begin{eqnarray} \mathrm{Arg}{\left(z\right)}&=&\mathrm{Arg}{\left(x+iy\right)} \\&=&\begin{cases} \tan^{-1}{\left(\frac{y}{x}\right)} & (x\gt0) \\\tan^{-1}{\left(\frac{y}{x}\right)+\pi} & (x\lt0\;かつ\;y\geq0) \\\tan^{-1}{\left(\frac{y}{x}\right)-\pi} & (x\lt0\;かつ\;y\lt0) \\\frac{\pi}{2} & (x=0\;かつ\;y\gt0) \\-\frac{\pi}{2} & (x=0\;かつ\;y\lt0) \\不定 & (x=0\;かつ\;y=0) \end{cases} \end{eqnarray}$$

xでの偏微分

$$\begin{eqnarray} \frac{\partial}{\partial x}\arg{\left(z\right)}&=&\frac{\partial}{\partial x}\left\{\theta+2n\pi\right\} \\&=&\frac{\partial}{\partial x}\left\{\mathrm{Arg}{\left(z\right)}+2n\pi\right\} \\&=&\frac{\partial}{\partial x}\mathrm{Arg}{\left(z\right)}+\frac{\partial}{\partial x}2n\pi \\&=&\frac{\partial}{\partial x}\mathrm{Arg}{\left(z\right)}\;\ldots\;\frac{\partial}{\partial x} C=0\;(Cは定数.xの凾数でない) \end{eqnarray}$$ $$\begin{eqnarray} \frac{\partial}{\partial x}\mathrm{Arg}{\left(z\right)}&=&\frac{\partial}{\partial x}\mathrm{Arg}{\left(x+iy\right)} \\&=&\begin{cases} \frac{\partial}{\partial x}\tan^{-1}{\left(\frac{y}{x}\right)} &=&\frac{-y}{x^2+y^2}& (x\gt0) \\\frac{\partial}{\partial x}\tan^{-1}{\left(\frac{y}{x}\right)+\pi} &=&\frac{-y}{x^2+y^2}& (x\lt0\;かつ\;y\geq0) \\\frac{\partial}{\partial x}\tan^{-1}{\left(\frac{y}{x}\right)-\pi} &=&\frac{-y}{x^2+y^2}& (x\lt0\;かつ\;y\lt0) \\\frac{\partial}{\partial x}\frac{\pi}{2} &=&0& (x=0\;かつ\;y\gt0) \\\frac{\partial}{\partial x}-\frac{\pi}{2} &=&0& (x=0\;かつ\;y\lt0) \\不定 &&& (x=0\;かつ\;y=0) \end{cases} \ldots\href{https://shikitenkai.blogspot.com/2021/07/tan^{-1}yx.html}{\frac{\partial}{\partial x}\tan^{-1}{\left(\frac{y}{x}\right)}=\frac{-y}{x^2+y^2}} \end{eqnarray}$$

yでの偏微分

$$\begin{eqnarray} \frac{\partial}{\partial y}\arg{\left(z\right)}&=&\frac{\partial}{\partial y}\left\{\theta+2n\pi\right\} \\&=&\frac{\partial}{\partial y}\left\{\mathrm{Arg}{\left(z\right)}+2n\pi\right\} \\&=&\frac{\partial}{\partial y}\mathrm{Arg}{\left(z\right)}+\frac{\partial}{\partial y}2n\pi \\&=&\frac{\partial}{\partial y}\mathrm{Arg}{\left(z\right)}\;\ldots\;\frac{\partial}{\partial y} C=0\;(Cは定数.xの凾数でない) \end{eqnarray}$$ $$\begin{eqnarray} \frac{\partial}{\partial y}\mathrm{Arg}{\left(z\right)}&=&\frac{\partial}{\partial y}\mathrm{Arg}{\left(x+iy\right)} \\&=&\begin{cases} \frac{\partial}{\partial y}\tan^{-1}{\left(\frac{y}{x}\right)} &=&\frac{x}{x^2+y^2}& (x\gt0) \\\frac{\partial}{\partial y}\tan^{-1}{\left(\frac{y}{x}\right)+\pi} &=&\frac{x}{x^2+y^2}& (x\lt0\;かつ\;y\geq0) \\\frac{\partial}{\partial y}\tan^{-1}{\left(\frac{y}{x}\right)-\pi} &=&\frac{x}{x^2+y^2}& (x\lt0\;かつ\;y\lt0) \\\frac{\partial}{\partial y}\frac{\pi}{2} &=&0& (x=0\;かつ\;y\gt0) \\\frac{\partial}{\partial y}-\frac{\pi}{2} &=&0& (x=0\;かつ\;y\lt0) \\不定 &&& (x=0\;かつ\;y=0) \end{cases} \ldots\href{https://shikitenkai.blogspot.com/2021/07/tan^{-1}yx.html}{\frac{\partial}{\partial y}\tan^{-1}{\left(\frac{y}{x}\right)}=\frac{x}{x^2+y^2}} \end{eqnarray}$$

arctan(y/x)の偏微分

\(\tan^{-1}{\left(\frac{y}{x}\right)}\)の偏微分

$$\begin{eqnarray} \theta&=&\tan^{-1}{\left(\frac{y}{x}\right)} \end{eqnarray}$$

\(\tan^{-1}{\left(\frac{y}{x}\right)}\)の\(x\)での偏微分

$$\begin{eqnarray} \frac{\partial }{\partial x}\tan^{-1}{\left(\frac{y}{x}\right)} &=&\left\{\frac{\partial }{\partial u}\tan^{-1}{\left(u\right)}\right\}\frac{\partial u}{\partial x} \;\ldots\;u=\frac{y}{x} \\&=&\frac{1}{1+u^2}\frac{\partial }{\partial x}\frac{y}{x} \;\ldots\;\href{https://shikitenkai.blogspot.com/2021/07/arctanx.html}{\frac{\partial }{\partial u}\tan^{-1}{\left(u\right)}=\frac{1}{1+u^2}} \\&=&\frac{1}{1+\frac{y^2}{x^2}}y\frac{\partial }{\partial x}x^{-1} \\&=&\frac{1}{\frac{x^2+y^2}{x^2}}y\left(-x^{-2}\right) \\&=&\frac{x^2}{x^2+y^2}y\left(-x^{-2}\right) \\&=&\frac{-y}{x^2+y^2} \end{eqnarray}$$

\(\tan^{-1}{\left(\frac{y}{x}\right)}\)の\(y\)での偏微分

$$\begin{eqnarray} \\\frac{\partial }{\partial y}\tan^{-1}{\left(\frac{y}{x}\right)} &=&\left\{\frac{\partial }{\partial u}\tan^{-1}{\left(u\right)}\right\}\frac{\partial u}{\partial y} \;\ldots\;u=\frac{y}{x} \\&=&\frac{1}{1+u^2}\frac{\partial }{\partial y}\frac{y}{x} \;\ldots\;\href{https://shikitenkai.blogspot.com/2021/07/arctanx.html}{\frac{\partial }{\partial u}\tan^{-1}{\left(u\right)}=\frac{1}{1+u^2}} \\&=&\frac{1}{1+\frac{y^2}{x^2}}x^{-1}\frac{\partial }{\partial y}y \\&=&\frac{1}{\frac{x^2+y^2}{x^2}}x^{-1}\cdot1 \\&=&\frac{x^2}{x^2+y^2}x^{-1} \\&=&\frac{x}{x^2+y^2} \end{eqnarray}$$