間違いしかありません.コメントにてご指摘いただければ幸いです(気が付いた点を特に断りなく頻繁に書き直していますのでご注意ください).

連続型確率変数(continuous random variable) の一様分布(uniform distribution)の分散(variance)

MX(m)(0)dmdmtMX(t)|t=0=E[XmetX]|t=0=E[Xm]

積率母凾数の二階微分

MX(2)=d2dt2{etbetat(ba)}=ddt{(tb1)etb(ta1)etat2(ba)}=1ba[(t2){(tb1)etb(ta1)eta}+(t2){(tb1)etb(ta1)eta}]=1ba[(2t3){(tb1)etb(ta1)eta}+(t2)[{(tb1)etb}{(ta1)eta}]]=1ba[(2t3){(tb1)etb(ta1)eta}+(t2)[{(tb1)etb+(tb1)(etb)}{(ta1)eta+(ta1)(eta)}]]=1ba[(2t3){(tb1)etb(ta1)eta}+(t2)[{betb+(tb1)betb}{aeta+(ta1)aeta}]]=1ba[2{(tb1)etb(ta1)eta}+t[{betb+(tb1)betb}{aeta+(ta1)aeta}]t3]=1t3(ba)[2(tb1)etb+2(ta1)eta+tbetb+tb(tb1)etbtaetata(ta1)eta]=1t3(ba)[{2(tb1)+tb+tb(tb1)}etb+{2(ta1)tata(ta1)}eta]=1t3(ba){((tb1)2+1)etb((ta1)2+1)eta}=((tb1)2+1)etb((ta1)2+1)etat3(ba)

原点周りの二次モーメント

E[X2]=MX(2)(0)=limt0{((tb1)2+1)etb((ta1)2+1)etat3(ba)}00=limt0[1t3(ba){((tb1)2+1)etb((ta1)2+1)eta}]=limt0[1t3(ba){((tb1)2+1)((tb)00!+(tb)11!+(tb)22!+(tb)33!)((ta1)2+1)((ta)00!+(ta)11!+(ta)22!+(ta)33!)}]ex=k=0xkk!=x00!+x11!+x22!+x33!+(),t3t4tt3=limt0[1t3(ba){(t2b22tb+2)(1+tb+t2b22+t3b36)(t2a22ta+2)(1+ta+t2a22+t3a36)}]=limt0[1t3(ba)[{(t2b2+t3b3+t4b42+t5b56)+(2tb2t2b2t3b3t4b43)+(2+2tb+t2b2+t3b33)}{(t2a2+t3a3+t4a42+t5a56)+(2ta2t2a2t3a3t4a43)+(2+2ta+t2a2+t3a33)}]]=limt0[1t3(ba){(2+t3b33+t4b46+t5b56)(2+t3a33+t4a46+t5a56)}]=limt0[1t3(ba){t3b3a33+t4b4a46+t5b5a56}]=limt0[1t3(ba){t3(ba)(b2+ab+a2)3+t4(ba)(b+a)(a2+b2)6+t5(ba)b5a5ba6}]=limt0{b2+ab+a23+t(b+a)(a2+b2)6+t2(b5a5ba)6}=b2+ab+a23=a2+ab+b23t()0

分散(二次の中心モーメント)

V[X]=E[X2]E[X]2=b2+ab+a23(b+a2)2=b2+ab+a23b2+2ab+a24=4(b2+ab+a2)3(b2+2ab+a2)12=4b2+4ab+4a23b26ab3a212=b22ab+a212=(ba)212

0 件のコメント:

コメントを投稿