間違いしかありません.コメントにてご指摘いただければ幸いです(気が付いた点を特に断りなく頻繁に書き直していますのでご注意ください).

逆行列の補題 / matrix inversion lemma / Sherman–Morrison–Woodbury formula

逆行列の補題 / matrix inversion lemma / Sherman–Morrison–Woodbury formula

A:n×nmatrixC:k×kmatrixU:k×nmatrixV:n×kmatrix の時, (A+UCV)1=A1A1U(C1+VA1U)1VA1

(A+UCV)()=In

(A+UCV)()=(A+UCV){A1A1U(C1+VA1U)1VA1}=(A+UCV)A1(A+UCV){A1U(C1+VA1U)1VA1}=AA1+UCVA1A{A1U(C1+VA1U)1VA1}UCV{A1U(C1+VA1U)1VA1}=In+UCVA1AA1U(C1+VA1U)1VA1UCVA1U(C1+VA1U)1VA1=In+U{C(C1+VA1U)1}VA1UCVA1U(C1+VA1U)1VA1=In+UC{(C1+VA1U)C1}(C1+VA1U)1VA1UCVA1U(C1+VA1U)1VA1XY1=XYY1XX1Y1=X(YX1)Y1=In+UC(VA1U)(C1+VA1U)1VA1UCVA1U(C1+VA1U)1VA1=In+UCVA1U(C1+VA1U)1VA1UCVA1U(C1+VA1U)1VA1=In

()(A+UCV)=In

()(A+UCV)={A1A1U(C1+VA1U)1VA1}(A+UCV)=A1A+A1UCVA1U(C1+VA1U)1VA1AA1U(C1+VA1U)1VA1UCV=In+A1UCVA1U(C1+VA1U)1VA1U(C1+VA1U)1VA1UCV=In+A1UCVA1U(C1+VA1U)1VA1U(C1+VA1U)1VA1UCV=In+A1U{C(C1+VA1U)1}VA1U(C1+VA1U)1VA1UCV=In+A1U(C1+VA1U)1{(C1+VA1U)C1}CVA1U(C1+VA1U)1VA1UCVXY1=Y1YXY1X1X=Y1(YX1)X=In+A1U(C1+VA1U)1(VA1U)CVA1U(C1+VA1U)1VA1UCV=In+A1U(C1+VA1U)1VA1UCVA1U(C1+VA1U)1VA1UCV=In

以上より

以上より右辺(A1A1U(C1+VA1U)1VA1)A+UCVの逆行列である.

C=Ikの時

またC=Ikの時は,C1=Ikでもあるので, (A+UV)1=A1A1U(Ik+VA1U)1VA1 となる.

0 件のコメント:

コメントを投稿